java file int array read

Question

I want to get an array of integers from the file .But when i get an array unwanted zeros are in the array as the size is 10 and there are only 5 integers in file(18,12,14,15,16). How to remove those zeros. Code is:

import java.io.File;
import java.io.IOException;
import java.util.Arrays;
import java.util.Scanner;



public class TxtFile {

public static void main(String[] args) {
    // TODO Auto-generated method stub
    File inFile=new File("H:\\Documents\\JavaEclipseWorkPlace\\ReadTextFile\\src\\txt.txt");
    Scanner in=null;
    int []contents = new int[10];
    int i=0;
    try {
        in=new Scanner(inFile);

        while(in.hasNextInt()){
             contents[i++]=in.nextInt();
        }
        System.out.println(Arrays.toString(contents));
    }
    catch(IOException e){
        e.printStackTrace();
    }
    finally{
        in.close();
    }

}

}

Output is: [18, 12, 14, 15, 16, 0, 0, 0, 0, 0].

If i want to sort it by insertion and then perform binary search can it be accomplished (on ArrayList)? — affanBajwa
– affanBajwa, Commented Apr 6, 2014 at 19:09

Jason C · Accepted Answer · 2014-04-06 19:02:18Z

2

This is because you allocate an array of size 10, and the values are initialized to 0 by default. Then you read the 5 values from the file, and this only overwrites the first 5 values in the array, the untouched 0's are still there.

You have a few options:

You could count the number of values you read from the file, then resize the array to match, e.g.:

while(in.hasNextInt()){
    contents[i++]=in.nextInt();
}

// 'i' now contains the number read from the file:
contents = Arrays.copyOf(contents, i);
// contents now only contains 'i' items.
System.out.println(Arrays.toString(contents));

You could count the number of values you read from the file, then only explicitly print that many values, e.g.:

while(in.hasNextInt()){
    contents[i++]=in.nextInt();
}

// 'i' now contains the number read from the file:
for (int n = 0; n < i; ++ n)
    System.out.println(contents[n]);

You could use a dynamic container like ArrayList<Integer>, and simply add values to it as you read them. Then you can support any number from the file automagically, e.g.:

ArrayList<Integer> contents = new ArrayList<Integer>();

...
while(in.hasNextInt()){
    contents.add(in.nextInt());
}

System.out.println(contents);

I recommend the third option. It is the most flexible and easiest to deal with.

edited Apr 6, 2014 at 19:02

answered Apr 6, 2014 at 18:56

Jason C

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1 Comment

affanBajwa Over a year ago

Thanks bro. I appriciate that.

Reimeus · Accepted Answer · 2014-04-06 18:55:59Z

1

Read the input file into an ArrayList<Integer> then call toArray to return an integer array

answered Apr 6, 2014 at 18:55

Reimeus

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Comments

NU113R · Accepted Answer · 2014-04-06 19:20:05Z

0

You can use a dynamic vector for this

import java.io.File;
import java.io.IOException;
import java.util.*;
class St{
 public static void main(String args[]){
 File inFile=new File("H:\\Documents\\JavaEclipseWorkPlace\\ReadTextFile\\src\\txt.txt");
Scanner in=null;
Vector<Integer> arr=new Vector<Integer>(5,2); //5 is initial size of vector, 2 is increment in size if new elements are to be added
try {
    in=new Scanner(inFile);

    while(in.hasNextInt()){
         arr.addElement(in.nextInt());
    }
arr.trimToSize(); // This will make the vector of exact size
    System.out.println(arr.toString());
}
catch(IOException e){
    e.printStackTrace();
}
finally{
    in.close();
}
}
}

answered Apr 6, 2014 at 19:20

NU113R

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