Return rows from multidimensional array based on value of an element

Question

$arr_ramones = array(
          1=>array('name'=>'johnny', 'display'=>1), 
          2=>array('name'=>'joey', 'display'=>1), 
          3=>array('name'=>'cj', 'display'=>0), 
          4=>array('name'=>'deedee', 'display'=>1), 
          5=>array('name'=>'marky', 'display'=>0)
  );

I'd like to loop through my array but only with rows that have a display value of 1.

I read how to do this with a regular array. Can something similar be done with multidimensional arrays without costing performance? My example array is small - real world example contains thousands of values.

If the 'real world' example array would contain thousands of values then really it should be held in a database, you would then be able to filter them as they are requested from the DB. — AeroX
– AeroX, Commented Apr 2, 2014 at 15:39

hsz · Accepted Answer · 2014-04-15 13:03:12Z

2

also works with array_filter.

$arr_ramones = array(
    1 => array('name'=>'johnny', 'display'=>1), 
    2 => array('name'=>'joey', 'display'=>1), 
    3 => array('name'=>'cj', 'display'=>0), 
    4 => array('name'=>'deedee', 'display'=>1), 
    5 => array('name'=>'marky', 'display'=>0)
);
$filter = array_filter($arr_ramones, function($arr) {
    return $arr['display'] == 1;
});

edited Apr 15, 2014 at 13:03

hsz

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answered Apr 2, 2014 at 15:41

Simon Wicki

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Comments

hsz · Accepted Answer · 2014-04-02 15:39:15Z

1

Just try with:

foreach ($arr_ramones as $item) {
  if ($item['display']) {
    echo $item['name'];
  }
}

or use array_filter

$display = array_filter($arr_ramones, function($item){
  return $item['display'];
});

foreach ($display as $item) {
  echo $item['name'];
}

answered Apr 2, 2014 at 15:39

hsz

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Comments

Community · Accepted Answer · 2023-11-17 19:41:46Z

1

Try array_walk if you just want to display data without creating new array. In case of creating array use array_map

array_walk($arr_ramones, function($a) { // displaying information from array based on requirements
    if ( $a['display'] == 1) {
        echo $a['name'] . " "; // johnny joey deedee 
    }
});

$n = array_map(function($a) { // creating new array based on requirements
    if ( $a['display'] == 1) {
        return $a['name'];
    }
}, $arr_ramones);

edited Nov 17, 2023 at 19:41

CommunityBot

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answered Apr 2, 2014 at 15:41

nanobash

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2 Comments

a coder Over a year ago

Is there a performance benefit in using array_walk as opposed to foreach?

nanobash Over a year ago

@acoder With performance they are pretty much the same while this function's algorithm uses loop as well, though it has another benefits. See this

Shankar Narayana Damodaran · Accepted Answer · 2014-04-02 15:47:54Z

0

A simple foreach like this.

foreach($arr as $k=>$arr)
{
 if($arr['display']==1)
  {
    echo $arr['name']."<br>";
  }
}

Using an array_filter

function filt($var)
{
   return $var['display']==1;
}  

$new_arr=array_filter ($arr_ramones,"filt" );
print_r($new_arr);

Demo

edited Apr 2, 2014 at 15:47

answered Apr 2, 2014 at 15:38

Shankar Narayana Damodaran

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2 Comments

a coder Over a year ago

Right, that came to mind immediately. Wondered if there is a function to essentially "query" the array.. so I could get a count of values having display=1.

Shankar Narayana Damodaran Over a year ago

@acoder, array_filter can be used too as shown in the illustration. I would prefer a foreach instead.

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