I have a decorator in Angular that is going to extend the functionality of the $log service and I would like to test it, but I don't see a way to do this. Here is a stub of my decorator:
angular.module('myApp')
.config(function ($provide) {
$provide.decorator('$log', ['$delegate', function($delegate) {
var _debug = $delegate.debug;
$delegate.debug = function() {
var args = [].slice.call(arguments);
// Do some custom stuff
window.console.info('inside delegated method!');
_debug.apply(null, args);
};
return $delegate
}]);
});
Notice that this basically overrides the $log.debug() method, then calls it after doing some custom stuff. In my app this works and I see the 'inside delegated method!' message in the console. But in my test I do not get that output.
How can I test my decorator functionality??
Specifically, how can I inject my decorator such that it actually decorates my $log mock implementation (see below)?
Here is my current test (mocha/chai, but that isn't really relevant):
describe('Log Decorator', function () {
var MockNativeLog;
beforeEach(function() {
MockNativeLog = {
debug: chai.spy(function() { window.console.log("\nmock debug call\n"); })
};
});
beforeEach(angular.mock.module('myApp'));
beforeEach(function() {
angular.mock.module(function ($provide) {
$provide.value('$log', MockNativeLog);
});
});
describe('The logger', function() {
it('should go through the delegate', inject(function($log) {
// this calls my mock (above), but NOT the $log decorator
// how do I get the decorator to delegate the $log module??
$log.debug();
MockNativeLog.debug.should.have.been.called(1);
}));
});
});
$logand then you override the entire$logwith a mock. So obviously in your test you will have a function with a simpledebugfunction. I guess I missed something along the way.angular.module()needs two arguments...angular.module(), but good catch anyway!