Python iterate through lists within tuple data structure

Question

I have the following data structure:

data = (['test1','test2','test3'], ['foo1','foo2','foo3'], ['bar1','bar2','bar3'])

I want to iterate through this data structure and create a new tuple which appends position 1 of each list to it. I would like to create a data structure with

(test1,foo1,bar1), (test2,foo2,bar2), (test3,foo3,bar3)

These are not valid data structures, you are missing commas. — placeybordeaux
– placeybordeaux, Commented Mar 17, 2014 at 18:01
I just wrote it to outline what it looks like...My apologies — Ciaran
– Ciaran, Commented Mar 17, 2014 at 18:02

mgilson · Accepted Answer · 2014-03-17 18:01:06Z

3

This is an easy zip with argument unpacking:

print zip(*data)

e.g.:

>>> data = (['test1','test2','test3'],['foo1','foo2','foo3'],['bar1','bar2','bar3'])
>>> zip(*data)
[('test1', 'foo1', 'bar1'), ('test2', 'foo2', 'bar2'), ('test3', 'foo3', 'bar3')]

answered Mar 17, 2014 at 18:01

mgilson

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Community · Accepted Answer · 2017-05-23 11:49:47Z

3

Unzip it via zip():

>>> data = (['test1','test2','test3'],['foo1','foo2','foo3'],['bar1','bar2','bar3'])
>>> zip(*data)
[('test1', 'foo1', 'bar1'), ('test2', 'foo2', 'bar2'), ('test3', 'foo3', 'bar3')]

Also see: Unzipping and the * operator.

edited May 23, 2017 at 11:49

CommunityBot

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answered Mar 17, 2014 at 18:01

alecxe

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