I have this string:
questioncode = YED_q2_a_10
I want to check if the string ends with an underscore then an int
i.e. "_293"
My attempt:
codesplit = questioncode.split('_')[-1]
if codesplit.isdigit():
print "true"
else:
print "false"
as you can see this is not doing what I want and I believe regex is the solution.
if questioncode.count('_') and questioncode.split('_')[-1].isdigit():
print 'true'
else:
print 'false'
is perfectly fine (and I'd say preferred), why do you want to use regular expressions? They're absolutely unnecessary here.
This statements check if there's at least one underscore in the string and splits the string if yes, so you won't get Index out of range error.
If you want you can replace questioncode.count('_') with '_' in questioncode, as suggested by @qwe.
'_' in questioncode makes more sense than calling .count().Try this one using re.search()
questioncode = "YED_q2_a_10"
if(re.search("_\d+$", questioncode)):
print "yes"
\d+ means any digit having one or more occurrence. And $ means the end of the string, an anchor.
import re
if re.match('.*_[0-9]+$', 'YED_q2_a_10'):
print "true"
else
print "false"
Simply see if you can convert string to int.
Here is the code. I assume there are one or more underscore in questioncode, so this only works when it is.
questioncode = "YED_q2_a_10"
codesplit = questioncode.split('_')[-1]
try:
int(codesplit)
print "true"
except ValueError:
print "false"
