PHP json_decode displaying blank

Question

<?php
$url = "http://api.giphy.com/v1/gifs/search?q=hello&api_key=dc6zaTOxFJmzC";
$content = file_get_contents($url);
$json = json_decode($content);
echo $json->images[0]->fixedheight->url[0];
?>

I've tried everything- even reading it as an array and it doesn't work.

Any help?

So sorry to bother! Thanks again.

Its non outputting anything.

user3399717
– user3399717

2014-03-13 05:16:02 +00:00
Commented Mar 13, 2014 at 5:16 — user3399717
– user3399717, Commented Mar 13, 2014 at 5:16
do a vardump of $json and see whay you are getting

Manquer
– Manquer

2014-03-13 05:19:37 +00:00
Commented Mar 13, 2014 at 5:19 — Manquer
– Manquer, Commented Mar 13, 2014 at 5:19

Shankar Narayana Damodaran · Accepted Answer · 2014-03-13 05:19:08Z

2

You should access it this way

echo $json->data[0]->images->fixed_height->url;

That is beacause the $data is an array , and it has an object as its first parameter.

answered Mar 13, 2014 at 5:19

Shankar Narayana Damodaran

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2 Comments

Rikesh Over a year ago

+1 - You can also suggest him to loop around to get all values not just a first one.

Shankar Narayana Damodaran Over a year ago

Thanks Rik , But seems like he needs just the URL .

ujash joshi · Accepted Answer · 2014-03-13 06:13:02Z

0

use this

 <?php
    $url = "http://api.giphy.com/v1/gifs/search?q=hello&api_key=dc6zaTOxFJmzC";
    $content = file_get_contents($url);
    $json = json_decode($content);
    echo "<pre>";
        print_r($json->data[0]->images->fixed_height->url);
    exit;
    ?>

answered Mar 13, 2014 at 6:13

ujash joshi

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