Strange Array output in java

Question

I would like to know why and how to fix this array method outputs the memory representation of temp.

public class StringMethodsExersice{
    public static int[] shiftMax(int[] num){
        int temp[] = new int[num.length];
        int firstEl = num[0];
        int lastEl = num[num.length-1];


        for(int i=1;i<num.length-1;i++){
            if(num[i] > num[i+1]){
                temp[i] = num[i];
            }
            temp[i] = num[i];
        }
        temp[0] = firstEl;
        temp[num.length-1]= lastEl;
        return temp;
    }

    public static void main (String []args){
        int[] myArray = new int [5];
        myArray [0] = 2;
        myArray [1] = 5;
        myArray [2] = 6;
        myArray [3] = 14;
        myArray [4] = 25;
        System.out.println(shiftMax(myArray));
    }
}

Maroun · Accepted Answer · 2014-03-09 13:52:18Z

5

You can use Arrays#toString:

System.out.println(Arrays.toString(shiftMax(myArray)));

(See its implementation for details)

Explanation about the output you're getting:

Since each object has toString() method, the default is displaying the class name representation, then adding @ sign and then the hashcode.

answered Mar 9, 2014 at 13:52

Maroun

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2 Comments

The Guy with The Hat Over a year ago

Stop stealing my answers! :P +1

fge Over a year ago

Also note the existence of Arrays.deepToString() for embedded arrays

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