Java if and else statements

Question

I am trying to make a simple text adventure game in Java and when I type Quit it ends the game. But instead it will ask if you want to do the quest even if you type quit which is suppose to end the code, I tried using loops to fix this error but had to luck. Any idea where I went wrong?

import java.util.*;

public class TextGame {
    public static void main(String[] args) {

        //Boolean run = true;
        //while (run){

        Scanner in = new Scanner(System. in );

        System.out.println("~SPECTRE~");
        System.out.println("");
        System.out.println("Please Choose One Below");
        System.out.println("");
        System.out.println("New");
        System.out.println("Quit");
        System.out.println("");

        String option;
        System.out.print("Select one of the options here: ");
        option = in .next();

        if (option.equals("New")) {
            System.out.println("Hello adventurer! Welcome to the land of Spectre.");

            String name;
            System.out.print("What is your name adventurer? ");
            name = in .next();
            System.out.println("Hello there! " + name);
        } else if (option.equals("Quit")) {
            System.out.println("*Returns to desktop*");
        }

        String quest;
        System.out.print("Would you like to go on a quest? ");
        quest = in .next();

        if (quest.equals("Yes")) {
            System.out.println("Here is a list of quests that I would like you to do ");
            System.out.println("");
            System.out.println("1) Fight the evil troll of Port Howlham");
            System.out.println("");
            System.out.println("2) Deliver supplys to the soliders in need");
            System.out.println("");
            System.out.println("3) Find the Kings lost son");
            System.out.println("");
            System.out.println("4) Find the Gemstone of Darlingbee to defeat the evil witch of Hobbitstone");

        } else {
            option.equals("");
            System.out.println("*Please pick New Game or Quit*");
        }
    }
}

Of course a program will continue processing instructions unless it has an instruction to stop. — Radiodef
– Radiodef, Commented Mar 1, 2014 at 5:37
I know that, but I didn't the code to do so since i'm new to Java. — user3312466
– user3312466, Commented Mar 1, 2014 at 5:55
It's just the way you asked the question--as if the program would terminate without being instructed to do so. So I felt the need to point out this fact since you'd be surprised the things some people don't have an understanding of. ; ) — Radiodef
– Radiodef, Commented Mar 1, 2014 at 6:02

user2575725 · Accepted Answer · 2014-03-01 05:32:32Z

6

try this:

} else if (option.equalsIgnoreCase("Quit")) {
    System.exit(0);
}

Or this:

} else if (option.equalsIgnoreCase("Quit")) {
    return;
}

answered Mar 1, 2014 at 5:32

user2575725

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1 Comment

user3312466 Over a year ago

Ah, I never knew this. Thanks for your help. Since i'm new to Java I really appreciate your help,

u3l · Accepted Answer · 2014-03-01 05:28:53Z

2

You're probably looking to exit the program. Use System.exit(0);

 else if(option.equals("Quit"))
{
    System.exit(0);
}

The 0 argument is a status code that indicates normal termination of the program.

answered Mar 1, 2014 at 5:28

u3l

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Comments

Christian Tapia · Accepted Answer · 2014-03-01 05:28:31Z

1

You can use System.exit(code) to finish the program. Put this at the end of the else if block:

if (option.equals("Quit") {
    ...
    System.exit(0);
}

The code can be any integer:

The argument serves as a status code; by convention, a nonzero status code indicates abnormal termination.

answered Mar 1, 2014 at 5:28

Christian Tapia

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