Create JsonArray from List

Question

I'd need to create a javax.json.JsonArray object (Java EE 7 API) from a java.util.List of JsonObjects. Formerly, when using JSON API I used to do it simply with:

JSONArray jsonArray = new JSONArray(list);

But I can see there's no equivalent constructor in javax.json.JsonArray. Is there a simple way (other than browsing across all the List) to do it ?
Thanks

Already checked. But Javadocs contains the following example:JsonArray value = Json.createArrayBuilder() .add(Json.createObjectBuilder() .add("type", "home") .add("number", "212 555-1234")) .add(Json.createObjectBuilder() .add("type", "fax") .add("number", "646 555-4567")) .build(); This is not what I have asked- I already have a List<JsonObjects> — user2824073
– user2824073, Commented Feb 20, 2014 at 13:27

Nicky Tellekamp · Accepted Answer · 2014-02-20 13:35:12Z

10

Unfortunately the standard JsonArrayBuilder does not take a list as input. So you will need to iterate over the list.

I don't know how your List looks but you could make a function like:

public JsonArray createJsonArrayFromList(List<Person> list) {
    JsonArray jsonArray = Json.createArrayBuilder();
    for(Person person : list) {
        jsonArray.add(Json.createObjectBuilder()
            .add("firstname", person.getFirstName())
            .add("lastname", person.getLastName()));
    }
    jsonArray.build();
    return jsonArray;
}

edited Feb 20, 2014 at 13:35

answered Feb 20, 2014 at 13:28

Nicky Tellekamp

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user2824073 Over a year ago

Thanks. It seems that's the only way to do it.

StefanHeimberg · Accepted Answer · 2018-01-03 10:11:43Z

1

If someone is interessted in how to do this with Java 8 Streams. The same code snippet:

public JsonArray createJsonArrayFromList(List<Person> list) {
    JsonArray jsonArray = Json.createArrayBuilder();
    list.stream().forEach(person -> jsonArray.add(Json.createObjectBuilder()
            .add("firstname", person.getFirstName())
            .add("lastname", person.getLastName())));
    jsonArray.build();
    return jsonArray;
}

answered Jan 3, 2018 at 10:11

StefanHeimberg

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