Array of pointer

Question

please help to fixed this program. I'm try to print array of pointer using pointer instead of array but i got this error:

pointer_multi_char4.c: In function ‘main’:
pointer_multi_char4.c:7:11: error: expected expression before ‘{’ token

this is the code:

#include <stdio.h>

int main (void){
char **message;
message= { "Four", "score", "and", "seven",
               "years", "ago,", "our", "forefathers" };
printf("%s\n",message);
return 0;
}

how can i fixed this code? please somebody explain me what's wrong with that code

Also, are you sure you don't just want to be using a char* to the string "Four score and seven years ago our forefathers"? — Linuxios
– Linuxios, Commented Feb 19, 2014 at 21:51

Ed Heal · Accepted Answer · 2014-02-19 21:56:45Z

5

#include <stdio.h>

int main (){
    char *message[] =  { "Four", "score", "and", "seven",
                         "years", "ago,", "our", "forefathers", 0 };

    int loop;
    for (loop = 0; message[loop]; ++loop) printf("%s\n",message[loop]);
    return 0;
}

The braces in this case (making an assumption) is that you want to initialise an array (hence the use of char *message[] instead of char **.

As it is an array need to loop over it. I used a null pointer to mark the end of the array

EDIT

Then @Lundu just need

#include <stdio.h>

int main()
{
    const char * mesage="Four scor and seven years .... forefathers";
    printf("%s\n", message);
    return 0;
}

edited Feb 19, 2014 at 21:56

answered Feb 19, 2014 at 21:51

Ed Heal

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3 Comments

Piotr Zierhoffer Over a year ago

What is worth mentioning, that in @EdHeal example the initialization is in the same line as declaration. If you make it as two separate instructions, it's no longer an initialization - it's an assignment.

Lundu Harianja Over a year ago

I'm tryng to print this message using pointer instead of array,

Ed Heal Over a year ago

@Smac89 - More speed less haste

BLUEPIXY · Accepted Answer · 2014-02-19 22:15:37Z

1

#include <stdio.h>

int main (void){
    char **message;
    message= (char* []){ "Four", "score", "and", "seven",
               "years", "ago,", "our", "forefathers" };
    int numOfMessage = 8;
    while(numOfMessage--){
        printf("%s\n", *message++);
    }
    return 0;
}

answered Feb 19, 2014 at 22:15

BLUEPIXY

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