Java invalid array size

Question

I taking a string input from console. If I input "abcd" and spilt like this way

Scanner input = new Scanner(System.in);
String[]stringInput = input.nextLine().toLowerCase().trim().split("");

Suppose, I have entered "abcd" as input, stringInput.length is showing 5. But, It should be 4 right ? What's wrong, I am doing here ? Any idea ? How can I solve that ?

String.split() is really not the method you should use to get individual characters out of a String. Use charAt() or substring() or toCharArray(). — JB Nizet
– JB Nizet, Commented Feb 17, 2014 at 7:59
Read about working of method split, u will get your answer...... — Mayank Tiwari
– Mayank Tiwari, Commented Feb 17, 2014 at 7:59

Abimaran Kugathasan · Accepted Answer · 2014-02-17 07:58:44Z

2

There is an empty String at the end.

Use split("", -1)

...., the array can have any length, and trailing empty strings will be discarded

answered Feb 17, 2014 at 7:58

Abimaran Kugathasan

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Baby · Accepted Answer · 2014-02-17 08:04:35Z

1

Using split("") there always be an extra empty element of array at the first index

to be sure, you can try:

System.out.println(Arrays.toString(stringInput));

Output:

[, a, b, c, d]

answered Feb 17, 2014 at 8:04

Baby

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Sinto · Accepted Answer · 2014-02-17 09:20:33Z

0

You can achieve it using regex in split method as follows:

split("(?!^)")

See more details on regex usage.

answered Feb 17, 2014 at 9:20

Sinto

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Standin.Wolf · Accepted Answer · 2014-02-17 08:01:16Z

0

There is an empty space always after a string.So you need to use in your case abcd and a space

Use split("", -1)

answered Feb 17, 2014 at 8:01

Standin.Wolf

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