I am doing the closure tutorial at http://clojurescriptkoans.com and I am stuck here: http://clojurescriptkoans.com/#functions/9
It looks like this
Higher-order functions take function arguments
(= 25 ( _ (fn [n] (* n n))))
I am supposed to fill in something at the underscore to make the expression true. I have no clue what to do.
The syntax simply consists of binding the function, and then calling it.
Since this is an exercise, I will show a similar situation rather than showing the exercise's solution:
user> ((fn [f] (f "abc")) (fn [s] (str s s s)))
"abcabcabc"
here I bind the argument of the first function to f, and call f with the argument "abc".
true in my repl.Higher order functions takes functions as arguments. Defining two functions
user=> (defn multiply [n] (* n n))
#'user/multiply
user=> (defn add [n] (+ n n))
#'user/add
Defining higher order function
user=> (defn highorderfn [fn number] (fn number))
#'user/highorderfn
Calling the higher order function
user=> (highorderfn multiply 5)
25
user=> (highorderfn add 5)
10
