If Statement Using JavaScript and PHP

Question

I want this div displayed on my page whenever there is a "Y" in the database.

<div style="width:100%; height:41px; position:fixed; bottom:0px; background:#184888;     padding:22px 0 0 15px;  bottom:0px; z-index:9997; box-shadow: 10px 10px 5px #888888;" id="hide">
<div id="message" style="z-index:9998;">  </div>

How would I make it so that the div is displayed and not displayed without refreshing the page. Basically I have to see if it is a "Y" in the database, and if it is, display the div. If an "N" is in the database do not display the div, using JavaScript.

I am currently using this function to see check the database for a value.

$('div#checkcheck').load('../bar/check.php/check.php');

What error do you get?

Daniel W.
– Daniel W.

2014-02-13 17:06:14 +00:00
Commented Feb 13, 2014 at 17:06 — Daniel W.
– Daniel W., Commented Feb 13, 2014 at 17:06

user2616876 · Accepted Answer · 2014-02-13 17:11:16Z

2

Pass an anonymous function to your jQuery load. This will be able to catch the value from check.php

$('div#checkcheck').load('../bar/check.php/check.php', function(response) {
  //do something with that response
});

answered Feb 13, 2014 at 17:11

user2616876

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Comments

Konza · Accepted Answer · 2014-02-13 17:07:54Z

0

Send an ajax request to your server. Let your php code check for the 'Y' in database. Your server call will return a json.

Use that json in javascript to check for 'Y' or'N' and then show/hide your div.

answered Feb 13, 2014 at 17:07

Konza

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Comments

putvande · Accepted Answer · 2014-02-13 17:11:58Z

0

$.get('../bar/check.php/check.php', function(response) {
    $('div#checkcheck')[response === 'Y' ? 'show' : 'hide']();
});

answered Feb 13, 2014 at 17:11

putvande

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Comments

SenorAmor · Accepted Answer · 2014-02-13 17:42:37Z

0

Try this:

$.getJSON('../bar/check.php/check.php', function(res){
    if(res === 'Y')
    {
        $('div').show();
    }
    else
    {
        $('div').hide();
    }
});

edited Feb 13, 2014 at 17:42

SenorAmor

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answered Feb 13, 2014 at 17:17

Jain

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