Sending information by javascript into PHP

Question

I want to send information of 1 variable with javascript into PHP.

So , i used this code (in index.php) :

<html>
    <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">
    <script>
        $.post('http://localhost/test/index.php', {
            name: $('.class').html();
        });
        $(document).ready(function(){
           $("#my_form").on("submit", function () {
               var hvalue = $('.class').text();
               $(this).append("<input type='hidden' name='name' value=' " + hvalue + " '/>");
        });
    });
</script>
<form action="" method="post" id="my_form">
    <div class="class" name="name">
        this is my div
    </div>
    <input type="submit" value="submit" name="submit" />
</form>
<?php 
    if(isset($_POST['name'])){ $name = $_POST['name']; } 
    echo $name;

But i see this error :

Notice: Undefined variable: name in C:\Program Files\EasyPHP-5.4.0RC4\www\test\index.php on line 22

What can i do ?

please distinguish between java and javascript. they are, despite their names, NOT the same, not even roughly. — Johannes H.
– Johannes H., Commented Feb 8, 2014 at 7:43

sachleen · Accepted Answer · 2014-02-08 07:42:16Z

1

$name is not defined. You have the echo outside of the if statement, move it inside the braces.

if(isset($_POST['name'])) {
  $name = $_POST['name'];
  echo $name;
}

Also, you post to submit.php but this code is for index.php... so you need to fix that, too.

answered Feb 8, 2014 at 7:42

sachleen

31.2k8 gold badges81 silver badges75 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

user3271403 Over a year ago

I tested your code too and i have fixed the "submit.php" but it dorsn't work again, also my browser doesn't redirect to "localhost/test/submit.php" . what can i do now ?

Farzad · Accepted Answer · 2014-02-08 08:17:41Z

also , In using jQuery , you didn't closed the tag :

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js">

close like this and use this code :

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
$.post('http://localhost/test/index.php', {
name: $('.class').html();
});
$(document).ready(function(){
   $("#my_form").on("submit", function () {
        var hvalue = $('.class').text();
        $(this).append("<input type='hidden' name='name' value=' " + hvalue + " '/>");
    });
});
</script>
<form action="submit.php" method="post" id="my_form">
<div class="class" name="name">
this is my div
</div>
<input type="submit" value="submit" name="submit" />
</form>

Collectives™ on Stack Overflow

Sending information by javascript into PHP

2 Answers 2

1 Comment

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

1 Comment

Comments

Your Answer

Sign up or log in

Post as a guest

Related