Write a regexp parsing URL

Question

I am trying to write a regex which will do the following

If I have url like

example.com?mask=33&filter=23423&mode=12

It will match substring filter=23423

I need also to consider that the url can be

example.com?filter=23423

Thanks in advance.

Might do: /filter=(\d+)/

techfoobar
– techfoobar

2014-02-06 08:27:13 +00:00
Commented Feb 6, 2014 at 8:27 — techfoobar
– techfoobar, Commented Feb 6, 2014 at 8:27
Once matched, what do you want to do with it?

Ja͢ck
– Ja͢ck

2014-02-06 08:28:50 +00:00
Commented Feb 6, 2014 at 8:28 — Ja͢ck
– Ja͢ck, Commented Feb 6, 2014 at 8:28
Thanks. I want to be able to change it...

Lambrusco.Newbie
– Lambrusco.Newbie

2014-02-06 08:32:35 +00:00
Commented Feb 6, 2014 at 8:32 — Lambrusco.Newbie
– Lambrusco.Newbie, Commented Feb 6, 2014 at 8:32

Fedor Skrynnikov · Accepted Answer · 2014-02-06 08:35:31Z

1

You may just not consider [\?&] in your regexp and put /filter=[0-9]*/ if you sure that there will not be any params like other_filter=987 in your url. If you may have such use substr on the resulted regexp like so

url.match(/[\?&]filter=[0-9]*/)[0].substr(1)

answered Feb 6, 2014 at 8:35

Fedor Skrynnikov

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