Launch program in python and later a python script that monitors the output files generated by the program

Question

I want to launch a program from python, in this case abaqus (a finite element analysis software), using:

os.system('abaqus job=' + JobName + ' user=' + UELname + ' interactive')

After say 5 minutes running the program I want to execute a python script that monitors some output files generated by abaqus. If a certain condition is met than the python script will terminate the abaqus job. There's a catch here. To read the output files I need to run the python script from abaqus:

os.system('abaqus cae noGUI=results2.py')

My question is this:

Can I do this simply by:

os.system('abaqus job=' + JobName + ' user=' + UELname + ' interactive')
time.sleep(300)
os.system('abaqus cae noGUI=results2.py')

I know that using interactive key makes ths system wait for the abaqus job to finish before doing other stuff. Therefore, I asssume this is not as simple as I'd like it to be. Any ideas?

Jimilian · Accepted Answer · 2014-02-05 18:47:18Z

2

Did you try subprocess module?

answered Feb 5, 2014 at 18:47

Jimilian

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chk · Accepted Answer · 2014-02-05 19:10:16Z

1

Logic seems fine, i would suggest you to use subprocess, instead of os.system. Since you are calling commands, you can run all these commands at once like this

cmdToRun = '\'abaqus job=\' + JobName + \' user=\' + UELname + \' interactive\' ; sleep 300; abaqus cae noGUI=results2.py'

edited Feb 5, 2014 at 19:10

answered Feb 5, 2014 at 18:49

chk

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