String tokenization python

Question

I wanted to split a string in python.

s= "ot.jpg/n"

I used str.split() but it gives me ['ot.jpg']. I want to get ot.jpg without brackets.

Did you maybe confuse "split" and "strip"?

Brave Sir Robin
– Brave Sir Robin

2014-01-30 15:30:16 +00:00
Commented Jan 30, 2014 at 15:30 — Brave Sir Robin
– Brave Sir Robin, Commented Jan 30, 2014 at 15:30

nmichaels · Accepted Answer · 2014-01-30 15:30:59Z

1

You want to use str.strip() to get rid of the newline. If you need to use split, it returns a list. To get the nth item from a list, index the list: ['foo', 'bar'][n].

Incidentally, naming your string str is a bad idea, since it shadows the built-in str function.

answered Jan 30, 2014 at 15:30

nmichaels

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bgporter · Accepted Answer · 2014-01-30 15:31:16Z

0

The return value of the split() method is always a list -- in this case, it's given you a single-element list theList = ['ot.jpg']. Like any list, you get what you want out of it by indexing it:

myString = theList[0]

answered Jan 30, 2014 at 15:31

bgporter

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justengel · Accepted Answer · 2014-01-30 15:34:34Z

0

sounds like you want replace.

s= "ot.jpg/n".replace("/n", "")
"ot.jpg"

answered Jan 30, 2014 at 15:34

justengel

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