Insert jquery in the php code

Question

How to put this code in my registration code in my program that if the registration is successful this will pop-up?? I'm new with jquery so i dont know how to do this stuff...help me guys please.

<script>
$(document).ready(function() {
    // show a dialog box when clicking on a link
    $("#success").on('click', function(e) {
        e.preventDefault();
    $.Zebra_Dialog('<strong>Congratulations </strong>' + 
    'You are now successfully registered!');
    });
 });
</script>

here is my php code:

<?php
    if(isset($_POST['save'])) {
        $fname = $_POST['fname'];
        $lname = $_POST['lname'];
        $position = $_POST['position'];
        $username = $_POST['username'];
        $password = $_POST['password'];
        $dateregistered = date("Y-m-d H:i:s");
        if (!$_POST['fname'] || !$_POST['lname'] || !$_POST['position'] || !$_POST['username'] || !$_POST['password'] ) {
            echo "You did not complete all of the required fields!";
        } else {
            $query="INSERT INTO users (position, fname, lname, username,password,dateregistered) VALUES ('$position','$fname','$lname','$username','$password',CURRENT_TIMESTAMP) ";
            mysql_query($query);
            if($query)
            echo "You Successfully Created an Account!";
        }
    }
?>

i want to replace the echo thing into jquery code...anyone know how???

Well, the easiest solution would be to echo out the jQuery code. — Realitätsverlust
– Realitätsverlust, Commented Jan 16, 2014 at 8:35
Well, adding code to the DOM with PHP doesnt offer much possibilites.^^ I guess you could work with DOMDocument, but thats too much effort only for a little textbox. — Realitätsverlust
– Realitätsverlust, Commented Jan 16, 2014 at 8:39
In my opinion it's the best solution to use an AJAX call and after succesfull callback show the popup(api.jquery.com/jquery.ajax).. You also could use a $_SESSION — GuyT
– GuyT, Commented Jan 16, 2014 at 8:45

Satish Sharma · Accepted Answer · 2014-01-16 09:21:03Z

1

append jquery function is your php code

<?php 

if(isset($_POST['save']))
{
   $fname = $_POST['fname'];
   $lname = $_POST['lname'];
   $position = $_POST['position'];
   $username = $_POST['username'];
   $password = $_POST['password'];
   $dateregistered = date("Y-m-d H:i:s");
   if (!$_POST['fname'] || !$_POST['lname'] || !$_POST['position'] || !$_POST['username'] || !$_POST['password'] ) 
   {
      echo "You did not complete all of the required fields!";
   }
   else
   {
      $query="INSERT INTO users (position, fname, lname, username,password,dateregistered)   VALUES ('$position','$fname','$lname','$username','$password',CURRENT_TIMESTAMP) ";
      mysql_query($query);
      if($query){
        echo "You Successfully Created an Account!";
        // append here your jquery code
        ?>
          <script>
             $(document).ready(function() {
                // show a dialog box when clicking on a link

                   $.Zebra_Dialog('<strong>Congratulations </strong>' + 
                      'You are now successfully registered!');

             });
          </script>
         <?php
      }
   }
}
//corrected indentation
?>

edited Jan 16, 2014 at 9:21

answered Jan 16, 2014 at 8:39

Satish Sharma

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1 Comment

pythonian29033 Over a year ago

no problem man, just check it next time, I was going to give this answer but you were first

Indrajeet Singh · Accepted Answer · 2014-01-16 08:46:53Z

    **Try this code.......**
    <?php 

    if(isset($_POST['save']))
    {
    $fname = $_POST['fname'];
    $lname = $_POST['lname'];
    $position = $_POST['position'];
    $username = $_POST['username'];
    $password = $_POST['password'];
    $dateregistered = date("Y-m-d H:i:s");
    if (!$_POST['fname'] || !$_POST['lname'] || !$_POST['position'] || !$_POST['username'] || !$_POST['password'] ) 
    {
echo "<script>
         $(document).ready(function() {
        $('#success').on('click', function(e) {
            e.preventDefault();
        $.Zebra_Dialog('<strong>Congratulations </strong>' + 
        'You did not complete all of the required fields!');
        });
     });
    </script>";
    }
    else
    {
       $query="INSERT INTO users (position, fname, lname, username,password,dateregistered)   VALUES ('$position','$fname','$lname','$username','$password',CURRENT_TIMESTAMP) ";
       if(mysql_query($query)){
           echo "<script>
         $(document).ready(function() {
        $('#success').on('click', function(e) {
            e.preventDefault();
        $.Zebra_Dialog('<strong>Congratulations </strong>' + 
        'You Successfully Created an Account!');
        });
     });
    </script>";
       }
    }
    }
    ?>

Aniket Kulkarni · Accepted Answer · 2014-01-16 09:07:25Z

0

You can simply use

echo "<script>alert('You Successfully Created an Account!')</script>";

edited Jan 16, 2014 at 9:07

Aniket Kulkarni

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answered Jan 16, 2014 at 8:39

Krishna

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Comments

Felix · Accepted Answer · 2014-01-16 09:36:32Z

0

Try to do like this:

if($query)
{
   ?>
      <script>
         $(document).ready(function() {
            $.Zebra_Dialog('<strong>Congratulations </strong>' + 
               'You are now successfully registered!');
         });
      </script>
    <?php
}

edited Jan 16, 2014 at 9:36

answered Jan 16, 2014 at 8:42

Felix

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