Assign Two values in shell script array

Question

I wonder , if we can save two values , for example , name and number , in the same array member , for example , i have write the following code to do this :

`array[$count]={$x , 1}`

where $x containe a string , but when i want to print the value that array[$count] have :

`echo "$count - $x1 - ${array[$count]} \n"`

it's give just the first value which is $x

glenn jackman · Accepted Answer · 2014-01-14 18:32:09Z

1

bash does not have multidimensional arrays, but you can fake it using associative arrays:

$ declare -A array
$ count=5
$ array[$count,name]="foobar"
$ array[$count,value]=1
$ for idx in "${!array[@]}"; do printf "%s\t%s\n" "$idx" "${array[$idx]}"; done
5,value 1
5,name  foobar

This requires bash version 4

answered Jan 14, 2014 at 18:32

glenn jackman

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10 Comments

user3137879 Over a year ago

does associative array is similar to hash in perl ? and another question , can i change 'value' , since it should not be a fixed value ?

glenn jackman Over a year ago

Yes, associative array is like a hash. But it can only store strings as values. You don't want to change the word "value" in the array index, you want to change the actual value (where I have "1").

user3137879 Over a year ago

okay "value" , what will be , in another word , what will be assign ?

glenn jackman Over a year ago

whatever is on the right-hand side of = will be assigned to the variable named on the left-hand side

user3137879 Over a year ago

but what will happen if we assign a value with key that already exist ?

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