is it possible to for loop 2 lists with another size with the smallest one "relooping"?
example:
list = [1,2,3,4,5,6,7,8,10]
list2 = [a,b]
newlist = []
for number, letter in zip(list, list2):
newlist.append(item)
newlist.append(item2)
The loop stops at [1a, 2b] cause there are no more items in list2, is it possible for list2 to start over until list1 is empty? ie: newlist = [1a,2b,3a,4b,5a,6b] etc?
thkx!
>>> l1 = [1,2,3,4,5,6,7,8,10]
>>> l2 = ['a','b']
>>>
>>> from itertools import cycle
>>>
>>> for number, letter in zip(l1, cycle(l2)):
... print number, letter
...
1 a
2 b
3 a
4 b
5 a
6 b
7 a
8 b
10 a
See itertools.cycle.
As an aside, you shouldn't use list as a variable name, since that name is already taken by the built-in function list().
Use itertools.cycle:
>>> from itertools import cycle
>>> l1 = [1,2,3,4,5,6,7,8,10]
>>> l2 = ['a','b']
>>> map(''.join, zip(map(str, l1), cycle(l2)))
['1a', '2b', '3a', '4b', '5a', '6b', '7a', '8b', '10a']
cycleis fun to use, so it's probably pretty common. :^)