Separating strings from an array of pointers

Question

I have two arrays of pointers, that is,

char *a[3]= {"man","dog","cat"};
char *b[3]= {"job","rain","sleep"};

I want to separate the three strings of both above into three different characters arrays and then I want to concatenate the string from *b[] to the end of string from *a[].

How can I accomplish this? I don't want to print the separated strings.

This question is off topic on Programmers. It would best be asked on Stack Overflow, however, the question doesn't meet their minimum requirements. Please read the Stack Overflow question checklist and edit your question to make it suitable for migration. — Bart van Ingen Schenau
– Bart van Ingen Schenau, Commented Dec 25, 2013 at 11:15
There is a need to provide a new array because expansion of the array can not be. — BLUEPIXY
– BLUEPIXY, Commented Dec 25, 2013 at 14:52
"... I want to separate the three strings of both above ..." there are six strings. — alk
– alk, Commented Dec 25, 2013 at 16:20
For one thing, it is illegal to use char * to point to string literals. You need const char *. — Siyuan Ren
– Siyuan Ren, Commented Dec 26, 2013 at 1:34
@Siyuan Ren: It is not illegal to use char * to point to string literals. Read the C Standard: For character string literals, the array elements have type char… If the program attempts to modify such an array, the behavior is undefined. — Armali
– Armali, Commented Nov 4, 2016 at 15:00

Vlad from Moscow · Accepted Answer · 2013-12-25 23:13:17Z

1

If I have understood correctly you want the following

char s[3][10];

for ( size_t i = 0; i < 3; i++ )
{
   strcpy( s[i], a[i] );
   strcat( s[i], " " );
   strcat( s[i], b[i] );
}

answered Dec 25, 2013 at 23:13

Vlad from Moscow

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