How to find byte in array of bytes using VB.NET

Question

How can I search within an array of byte for a specific byte?

For example, I use Instr(String, "something to search") or InstrRev(String, "something to search") for strings. I basically don't want to loop through the byte array, because I have extremely long byte arrays and I want to search bytes in a flash.

I just need the fastest and the simplest code possible for my task.

What would be a faster quicker and simpler way to search? A byte array of a file, or to stream a file with filestream and then to search within it?

Bjørn-Roger Kringsjå · Accepted Answer · 2013-12-22 12:23:32Z

2

The System.Array class exposes many useful methods when working with arrays.

Dim [array] As Byte() = New Byte() {1, 2, 4, 6, 3}
Dim find As Byte = 3
Dim index As Integer = System.Array.IndexOf(Of Byte)([array], find)

If (index = -1) Then
    'Not found...
Else
    'Found!
End If

answered Dec 22, 2013 at 12:23

Bjørn-Roger Kringsjå

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3 Comments

Afnan Makhdoom Over a year ago

Can you please tell me how can I find the index of 2 or more consecutive byte patterns? The same way?

Bjørn-Roger Kringsjå Over a year ago

@AfnanMakhdoom Take a look at this post, byte() array pattern search. Convert the code at developerfusion.

Afnan Makhdoom Over a year ago

how can I search multiple points of one array in another array, for example array1(2) + array1(3) + array1(4) in another array say array2?

Peter Mortensen · Accepted Answer · 2016-07-01 10:02:18Z

0

Use:

Dim Tag As Byte, cTag() As Byte = UTF8Encoding.UTF8.GetBytes("Host: ")  ' For poc
Dim Ret As Byte, cTagLength as Byte = cTag.Length 'POS

For Each Ret In cBuffer 'Ret pos seek "Host: "
    If cBuffer(Ret) = cTag(Tag) Then
        Tag = +1 ' Avryleter
    Else
        Tag = 0 ' Reset
    End If
    If Tag = cTagLength Then 
        Exit For
    End If
Next

It still the same code (in VB.NET).

edited Jul 1, 2016 at 10:02

Peter Mortensen

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answered Nov 13, 2014 at 20:54

Shabeer Shabeer

1

1 Comment

Scott Solmer Over a year ago

Is this a new question or are you attempting to answer the original question?

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