Manipulating strings python 2.7

Question

I am trying to code a program that will insert specific numbers before parts of an input, for example given the input "171819-202122-232425" I would like it to split up the number into pieces and use the dash as a delimiter. I have split up the number using list(str(input)) but have no idea how to insert the appropriate numbers. It has to work for any number Thanks for the help.

Output =

     (number)17
     (number)18                
     (number)19
     (number+1)20
     (number+1)21
     (number+1)22
     (number+2)23
     (number+2)24
     (number+2)25

Add a number every 2 digits in the input? That's what you want? — Christian Tapia
– Christian Tapia, Commented Dec 14, 2013 at 3:30

Pekka · Accepted Answer · 2013-12-14 07:22:00Z

1

You could use split and regexps to dig out lists of your numbers:

Code

import re

mynum = "171819-202122-232425"
start_number = 5
groups = mynum.split('-') # list of numbers separated by "-"
number_of_groups = xrange(start_number , start_number + len(groups))

for (i, number_group) in zip(number_of_groups, groups):
    numbers = re.findall("\d{2}", number_group) # return list of two-digit numbers
    for x in numbers:
            print "(%s)%s" % (i, x)

Result

(5)17
(5)18
(5)19
(6)20
(6)21
(6)22
(7)23
(7)24
(7)25

answered Dec 14, 2013 at 7:22

Pekka

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Comments

Christian Tapia · Accepted Answer · 2013-12-14 03:37:56Z

0

Try this:

Code:

mInput = "171819-202122-232425"
number = 9 # Just an example
result = ""

i = 0
for n in mInput:
    if n == '-': # To handle dash case
        number += 1
        continue
    i += 1
    if i % 2 == 1: # Each two digits
        result += "\n(" + str(number) + ")" 
    result += n # Add current digit

print result

Output:

(9)17
(9)18
(9)19
(10)20
(10)21
(10)22
(11)23
(11)24
(11)25

answered Dec 14, 2013 at 3:37

Christian Tapia

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