Correctly combining javascript with php

Question

little help here please....I was writing a php script for a message system. comments are displayed in php with the use of $comments through a function. I was trying to use a light box in javascript, so that user will have the option to delete each comment. How can I combine the following php script with the javascript code:

<?php

$comments .= " <font size='3'>   ?>

<a href = "javascript:void(0)" onclick = "document.getElementById('light').style.display='block';document.getElementById('fade').style.display='block'">**Delete**</a>
    <div id="light" class="white_content">

        <form action="<?php=$_SERVER['PHP_SELF'];?>" method="post">
        <input type="submit" name="submit_1" value="Delete Photo" >
        </form>

    <a href = "javascript:void(0)" onclick = "document.getElementById('light').style.display='none';document.getElementById('fade').style.display='none'"><button>&nbsp;&nbsp;&nbsp;&nbsp;Cancel&nbsp;&nbsp;&nbsp;&nbsp;</button></a></div>
    <div id="fade" class="black_overlay"></div>             




<?php  $comments .= "</font>"; ?>

DimeCadmium · Accepted Answer · 2013-12-11 17:30:19Z

<?php
$comments .= <<<EOD
<font size='3'>
<a href="javascript:void(0)" onclick="document.getElementById('light').style.display='block';document.getElementById('fade').style.display='block'">**Delete**</a>
    <div id="light" class="white_content">
        <form action="$_SERVER[PHP_SELF]" method="post">
        <input type="submit" name="submit_1" value="Delete Photo" >
        </form>

        <a href="javascript:void(0)" onclick="document.getElementById('light').style.display='none';document.getElementById('fade').style.display='none'"><button>&nbsp;&nbsp;&nbsp;&nbsp;Cancel&nbsp;&nbsp;&nbsp;&nbsp;</button></a>
    </div>
    <div id="fade" class="black_overlay"></div>             
</font>
EOD;
?>

Something like that should work. Remember that the "EOD;" needs to be on it's own, at the very beginning of a line.

See also http://www.php.net/manual/en/language.types.string.php#language.types.string.syntax.heredoc

You're trying to use the "?> html... " construct incorrectly. It doesn't "return" the string, it prints it out directly - it will get sent to the browser whenever the parser passes over it, rather than being added to $comments

Samuel Cook · Accepted Answer · 2013-12-11 17:26:35Z

1

There are two syntax errors:

1, You're missing the closing double quotes from line 3:

$comments .= " <font size='3'> "

2, <?php= is invalid and should be used as:

<?php echo or <?= (shorthand echo statements must be enabled to use <?=)

here: <form action="<?=$_SERVER['PHP_SELF'];?>" method="post">

If you're looking to make your entire block of code 1 string then i would recommend using a heredoc statement like:

<?php

$comments .= <<<EOD
    <font size="3">
        <a href = "javascript:void(0)" onclick = "document.getElementById('light').style.display='block';document.getElementById('fade').style.display='block'">**Delete**</a>
        <div id="light" class="white_content">
            <form action="{$_SERVER['PHP_SELF']}" method="post">
                <input type="submit" name="submit_1" value="Delete Photo" >
            </form>
            <a href = "javascript:void(0)" onclick = "document.getElementById('light').style.display='none';document.getElementById('fade').style.display='none'"><button>&nbsp;&nbsp;&nbsp;&nbsp;Cancel&nbsp;&nbsp;&nbsp;&nbsp;</button></a>
        </div>
        <div id="fade" class="black_overlay"></div>
    </font>
EOD;

?>

answered Dec 11, 2013 at 17:26

Samuel Cook

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1 Comment

user2491321 Over a year ago

did it...still nothing

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