I have an array named test which has these contents:
a b c d e f.
I got these array from string which has :
a/b/c/d/e/f
I split the above string to an array using this:
test=$(echo $dUrl | tr "/" "\n")
Now I wish to get the test's first element using ${test[1]}, but its giving me nothing.
Where I'm making the mistake.
A Bash only solution would be to use word splitting and IFS for that.
var="a/b/c/d/e/f"
IFS=/; # redefine word-splitting on slash character
arr=( $var ) # use word-splitting :)
Using the read built-in is more secure:
var="a/b/c/d/e"
IFS=/ read -rd '' -a arr <<<"$var"
-r: disables interpretion of backslash escapes and line-continuation in the read data ;-a <ARRAY>: store in <ARRAY>, read the data word-wise into the specified array instead of normal variables ;-d <DELIM>: recognize <DELIM> as data-end, rather than <newline>.echo "${arr[0]}" # → a
echo "${arr[1]}" # → b
echo "${arr[2]}" # → c
test is not an array but a multiline string in your script, one way to get an element (eg the second) would be:
echo "$test" | sed -n '2p'
If you want to build a real array, you can use that syntax:
typeset -a test=( $(echo $dUrl|tr "/" " ") )
Then, ${test[2]} whill show you the second element as you expect.
You have to convert a string to array before you index it.
Like
arr=($test)
echo ${arr[2]}
As per your question
$ dUrl="a/b/c/d/e/f"
$ test=$(echo $dUrl | tr "/" "\n")
$ echo $test
a b c d e f
$ a=($test)
$ echo ${a[1]}
b
