I am newbie to Python and programming environment .Now I am studying python via online .I Landed up a small trouble while studying If Statements . The IF statement is currently interpreting while the ELSE statement is written it displays me a syntax error attached Screen Shot will make my problem understandble more clearly:
not only ELSE statement even ELIF statement also displays a syntax error.
the if and else need to be indented the same amount
for example
x = 5
if 8 > x:
print "8 is greater than x"
else:
same goes for elif
x = 5
if 8 > x:
print "8 is greater than x"
elif 8 < x:
print "8 is less than x"
else:
Indentation is everything in python. By
if x%2==0:
print "even"
else:
^^^
You mean to say that the else statement also comes under the if block, as it is one block of indent after the if statement. This throws an error as there is no if for the else that you have given. Now lets come to the correct way:
if x%2==0:
print "even"
else:
print "odd"
Here, since if and else are in the same indent, the else is corresponding to the if, and the else is executed if the if condition fails.
Check your spacing, else should be under if
if (x%2 == 0):
print "x is even"
else:
print "x is odd"
