Replacing elements in an array in Python

Question

I want to look in an array of elements. If an element exceeds a certain value x, replace it with another value y. It could be a bunch of elements that need to be replaced. Is there a function (code) to do this at once. I don't want to use for loop. Does the any() function help here? Thanks

By "array", do you mean list?

DSM
– DSM

2013-12-03 18:29:22 +00:00
Commented Dec 3, 2013 at 18:29 — DSM
– DSM, Commented Dec 3, 2013 at 18:29

shad0w_wa1k3r · Accepted Answer · 2013-12-03 18:31:04Z

2

I really don't know how one could possibly achieve such a thing without the if statement.

Don't know about any() but I gave it a try with map since you don't want a for loop. But, do note that the complexity order (Big O) is still n.

>>> array = [1, 2, 3, 4, 2, -2, -3, 8, 3, 0]
>>> array = map(lambda x: x if x < 3 else 2, array)
>>> array
[1, 2, 2, 2, 2, -2, -3, 2, 2, 0]

Basically, x if x < 3 else 2 works like If an element exceeds a certain value x, replaces it with another value y.

answered Dec 3, 2013 at 18:31

shad0w_wa1k3r

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2 Comments

Daniel Over a year ago

I think list comprehension is better than map lambda.

shad0w_wa1k3r Over a year ago

@Dani the OP did not want a use of for, hence no list comprehension.

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