I need an 2d array [9,16] with 144 numbers from 1->36 in random order (so each number is repeated 4 times).
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It sounds more like you want a shuffle algorithm. The numbers themselves are not random at all - just their order. I suggest editing the question to clarify that.Eilon– Eilon2010-01-09 04:45:53 +00:00Commented Jan 9, 2010 at 4:45
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3 Answers
Something like:
sourcearr = array();
for(i = 0; i < 36; i++){
for(j = 0; j < 4; j++){
sourcearr[i+j] = i;
}
}
sourcearr = shuffle(sourcearr)
k = 0;
myrandarr = array();
for(i = 0; i < 9; i++){
myrandarr[i] = array();
for(j = 0; j < 16; j++){
myrandarr[i][j] = sourcearr[k++];
}
}
where you use shuffle.
2 Comments
A New Chicken
I forgot to say that each number is repeated 4 times, it isn't just random.
A New Chicken
So there is nothing such as: Enumerable.Range(1,36)?
Assuming you don't care about the distribution, just store the results of
Math.floor(Math.random()*36) + 1
for each element of the array
1 Comment
Jerod Venema
This won't repeat each number 4 times however.
How's about:
var source = array();
var shuffled = array();
for(var i=0;i<4;i++)
{
for(var j=0; j<36;j++)
{
source[i*j] = j+1;
}
}
while( source.length > 0 )
{
var index = Math.floor(Math.random()*source.length);
var element = source.splice(index,1);
shuffled.push(element);
}
