Getting the URL before making the request on AngularJS $resource module

Question

I am consuming a REST api using Angular JS, using $resource module. I have to encode the URL using a private key and send the results of the encoding process on a header. I am trying to intercept the request and getting the requested URL, but I could not do that.

return $resource(url, {}, {
    get: { method: 'GET', headers: headers, transformRequest: function(data, headersGetter) {
        // Here "data" is undefined.  headersGetter() returns the headers. 
        // I need the URL here
    } 
});

Any help?

zs2020 · Accepted Answer · 2015-06-04 18:09:04Z

1

It sounds like what you want is an interceptor. Find the Interceptors section of the $http documentation. It would look something like this:

// register the interceptor as a service
$provide.factory('myHttpInterceptor', function($q, dependency1, dependency2) {
    return {
        // optional method
        'request': function(config) {
            //modify headers in config based on url in config
            return config;
        },
    }
});

Then register the interceptor like this:

app.config(['$httpProvider', function ($httpProvider) {
    $httpProvider.interceptors.push('myHttpInterceptor');
}]);

edited Jun 4, 2015 at 18:09

zs2020

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answered Nov 26, 2013 at 19:12

dnc253

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