Can I extend a string using StringBuilder?

Question

Quick question most likely very simple.

Basically, I need to change a string from obdurate to obliteration. I'm aware of the methods that I can use with StringBuilder but I'm unable to insert anything after the initial string. Is there anyway to add more characters?

my code is as follows

public class SimpleString {

public static void main (String [] args){

StringBuilder s1 = new StringBuilder ("obdurate");

s1.delete(2, 7);
s1.replace(2, 7, "lite");
s1.insert(8,15, "ration");   //the problem line.



System.out.println(s1);

The code here doesn't even compile (Java 7), so I can't imagine you bothered looking at the javadoc, which explains that the index must be < string.length() (for the actual insert() methods anyway) — biggusjimmus
– biggusjimmus, Commented Nov 21, 2013 at 18:13
please refer this docs.oracle.com/javase/7/docs/api/java/lang/StringBuffer.html ,the way you call the insert method is wrong — user1801279
– user1801279, Commented Nov 21, 2013 at 18:16

toasted_flakes · Accepted Answer · 2013-11-21 18:01:12Z

3

Use StringBuilder.append(String str)

s1.append("ration");

answered Nov 21, 2013 at 18:01

toasted_flakes

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Math · Accepted Answer · 2013-11-21 17:59:02Z

1

Use the append():

s1.append("ration");

answered Nov 21, 2013 at 17:59

Math

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1 Comment

toasted_flakes Over a year ago

Append doesn't exist with indexes.

jandresrodriguez · Accepted Answer · 2013-11-21 18:03:39Z

1

you can try the following:

public class SimpleString {

public static void main (String [] args){

StringBuilder s1 = new StringBuilder ("obdurate");

s1.delete(2, 7);
s1.replace(2, 7, "lite");
s1.append("ration");  

System.out.println(s1);

answered Nov 21, 2013 at 18:03

jandresrodriguez

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John B · Accepted Answer · 2013-11-21 18:06:04Z

0

s1.delete(2, s1.length());
s1.append("literation");

answered Nov 21, 2013 at 18:06

John B

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user1801279 · Accepted Answer · 2013-11-21 18:07:26Z

0

Try this

   public static void main(String[] args){

        StringBuilder s1 = new StringBuilder ("obdurate");

        s1.delete(2, 7);
        s1.replace(2, 7, "lite");
        s1.append("ration");

        System.out.println(s1);
    }

answered Nov 21, 2013 at 18:07

user1801279

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Comments

JoeC · Accepted Answer · 2013-11-21 18:08:16Z

0

Assuming you wanna insert a string into s1, the best way of doing it would be

for (int start = 0, start < 7; start ++) // assuming you wanna insert a string with length 7
    s1.append(" ")
// s1 = "obdurate      " then now you can insert a new string easily
// you can now insert in between (i guess by using insert, you don't just want the string to be added in the end)
s1.insert(3,10, "rationa"); // s1 = "obdrationaurate";

answered Nov 21, 2013 at 18:08

JoeC

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Sage · Accepted Answer · 2013-11-21 18:10:41Z

0

I need to change a string from obdurate to obliteration.

Make use of indexOf(str) with replace(stIndx, endIndx, replacement) function:

StringBuilder builder = new StringBuilder("obdurate it is");
int stIndex = builder.indexOf("obdurate");
int endIndex = stIndex + "obdurate".length(); // Find the end of the replacing string
builder.replace(stIndex, endIndex, "obliteration");

Is there anyway to add more characters?

use strBuilder.append(String) function, where strBuilder is an instance of StringBuilder

edited Nov 21, 2013 at 18:10

answered Nov 21, 2013 at 18:04

Sage

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