Im new to classes and I dont really know how to do this. Since Im new to using classes and very bad at searching I decided to ask here. What I want is a function from a class passed to another function in a class.
I tried to call it as below but it couldnt find the variable $b
For example:
class a {
function one() {
$b->two();
}
}
class b {
function two() {
echo "two";
}
}
$a = new a();
$b = new b();
How do i achieve this?
Thanks in advance!
You need to learn about Dependency Injection. In this case, A depends on B, so you need to pass it into A when instantiating A. Also, it's the standard naming convention to capitalize class names. It helps readability.
class A {
public function __construct(B $B) {
$this->B = $B;
}
public function one() {
$this->B->two();
}
}
class B {
public function two() {
echo "two";
}
}
$B = new B();
$A = new A($B);
$A->one();
$this. @ilpaijin's answer is another way you can do this using a mutator aka setter.There are many ways to achieve it and a lot of things to say before this example, just by learning more u'll discover all by yourself. By the way one of them:
class A {
public $b;
public function __construct(B $b)
{
$this->b = $b;
}
function one()
{
$this->b->two();
}
}
class B
{
function two()
{
echo "two";
}
}
$b = new B();
$a = new A($b);
$a->one();
-------EDIT-------
After knowing that still use a constructor and in case you can't modify it, u need to use what is called an setter or mutator method.
class A {
public $b;
public function setB(B $b)
{
$this->b = $b;
}
...
}
class B {
...
}
$b = new B();
$a = new A();
$a->setB($b);
$a->one();
You can't do it like that..
What you should read about is: "inheritance" in PHP.
basically doing this will allow you to achieve somewhat understanding of it:
class A extends B {
function one() {
$this->two();
}
}
class B {
function two() {
echo "two";
}
}
class a {
function one() {
$b = new b();
$b->two();
}
}
class b {
function two() {
echo "two";
}
}
$a = new a();
$a->one();
Output:
two
