Can you do something like this were Java is a java library
class TryStuff(method:() => Any) {
private val lib: Java = new Java
val tryStuff:TryStuff = new TryStuff(lib.method)
}
Is there someway to convert lib.method to a scala object
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1What do you mean by library? Package? I don't see anything problematic in the codedmitry– dmitry2013-11-16 12:57:52 +00:00Commented Nov 16, 2013 at 12:57
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2 Answers
val tryStuff:TryStuff = new TryStuff(x => lib.method(x))
or more concisely
val tryStuff:TryStuff = new TryStuff(lib.method _)
3 Comments
janos
or more concisely:
val tryStuff = new TryStuff(lib.method _)
Marco
It does not compile. The 'method' function passed in the TryStuff constructor does not take parameter.
Robin Green
It was just an example, the original code did not compile either.
You do not need to do anything special. Java methods are ready to be invoked in the Scala code.
In your example any method that does not have parameters can be used, in this case I use the method exists() of class java.io.File:
import java.io.File
class TryStuff(method:() => Any) {
private val lib: File = new File("a.file")
val tryStuff:TryStuff = new TryStuff(lib.exists)
}
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