Array as struct database?

Question

I have a struct that reads data from the user:

typedef struct
{
    int seconds;
} Time;

typedef struct
{
    Time time;
    double distance;
 } Training;


 Training input;

 scanf("%d %lf", input.time.seconds, input.distance);

This scanf will be looped and the user can input different data every time, I want to store this data in an array for later use. I THINK I want something like arr[0].seconds and arr[0].distance.

I tried to store the entered data in an array but it didn't really work at all...

Training data[10];

data[10].seconds = input.time.seconds;
data[10].distance = input.distance;

The data will wipe when the program closes and that's how I like it to be. So I want it to be stored in an array, no files or databases!

When you declare Training data[10];, you can only access elements 0..9. — Jonathan Leffler
– Jonathan Leffler, Commented Nov 12, 2013 at 21:55

el.pescado - нет войне · Accepted Answer · 2013-11-12 21:54:29Z

1

data[10] is of type Training which does not have seconds. Try:

Training data[10];

data[10].time.seconds = input.time.seconds;
data[10].distance = input.distance;

answered Nov 12, 2013 at 21:54

el.pescado - нет войне

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1 Comment

Jonathan Leffler Over a year ago

You can't use subscript 10 on an array Training data[10]; because the valid subscripts run from 0 to 9.

Josh B · Accepted Answer · 2013-11-12 21:56:43Z

0

Two things, the training set has a 'time' field to access the seconds, and if you define an array of 10 element, you can only use data[0] to data[9], data[10] will be past the end of the array.

Training data[10];

data[0].time.seconds = input.time.seconds;
data[0].distance = input.distance;

....

data[9].time.seconds = input.time.seconds;
data[9].distance = input.distance;

answered Nov 12, 2013 at 21:56

Josh B

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