Programmatically Upload Files in Django

Question

I have checked several other threads but I am still having a problem. I have a model that includes a FileField and I am generating semi-random instances for various purposes. However, I am having a problem uploading the files.

When I create a new file, it appears to work (the new instance is saved to the database), a file is created in the appropriate directory, but the file's content is missing or corrupt.

Here is the relevant code:

class UploadedFile(models.Model):
  document = models.FileField(upload_to=PATH)


from django.core.files import File

doc = UploadedFile()
with open(filepath, 'wb+') as doc_file:
   doc.documen.save(filename, File(doc_file), save=True)
doc.save()

Thank you!

Andre Bossard · Accepted Answer · 2012-09-17 04:48:00Z

28

Could it be as simple as the opening of the file. Since you opened the file in 'wb+' (write, binary, append) the handle is at the end of the file. try:

class UploadedFile(models.Model):
  document = models.FileField(upload_to=PATH)


from django.core.files import File

doc = UploadedFile()
with open(filepath, 'rb') as doc_file:
   doc.document.save(filename, File(doc_file), save=True)
doc.save()

Now its open at the beginning of the file.

edited Sep 17, 2012 at 4:48

Andre Bossard

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answered Jan 3, 2010 at 4:18

JudoWill

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3 Comments

Jerzyk Over a year ago

why do you save a whole model? isn't it redundant (called earlier by doc.document.save() with save=True)

elena Over a year ago

I have actually had a similar problem and adding the 'b' flag solved the problem - I was opening pdf files.

Matt Over a year ago

What is filename ?

Ivan Rostovsky · Accepted Answer · 2023-06-15 08:38:18Z

2

For pdf files I used the receipt from django doc: https://docs.djangoproject.com/en/4.2/topics/files/

from pathlib import Path

from django.core.files import File

class Invoice(TimeStampedModel):
    magnifinance_file = models.FileField(blank=True, null=True)

invoice = Invoice.objects.get(pk=1)
path = Path('/path_to_file/mf_invoice.pdf')
with path.open(mode="rb") as f:
     invoice.magnifinance_file = File(f, name=path.name)
     invoice.save()

answered Jun 15, 2023 at 8:38

Ivan Rostovsky

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