preg_match in PHP or similar function in javascript

Question

I have to use a regular expression to get the text after the last "/" and before "_completed" string.

For example if my input is :

http://localhost/project-1/uploaded_images/output//11-03-2013+11-09-2013/Brian_Brown_completed.jpg

I need to output "Brian Brown" is that possible with preg_match? Unfortunately I could not figure it out! How about the javascript is it possible there too?

If you need more clarification, please let me know!

EDITED:

Please note that in output I dont have underscore anymore!

Many thanks in advance,

Yes, it's possible in both PHP and Javascript. What have you tried that didn't work? — Barmar
– Barmar, Commented Nov 11, 2013 at 16:45
I was trying preg_match but I dont know how to pass the pattern! — user385729
– user385729, Commented Nov 11, 2013 at 16:47
I didn't downvote, but I'll bet it was because your question looks like you've made no attempt to solve the problem yourself. There are thousands of questions here with examples of using preg_match. — Barmar
– Barmar, Commented Nov 11, 2013 at 16:54

Tushar Gupta - curioustushar · Accepted Answer · 2013-11-11 16:45:35Z

1

With JavaScript

Fiddle DEMO

var str = 'http://localhost/project-1/uploaded_images/output//11-03-2013+11-09-2013/Brian_Brown_completed.jpg ';
console.log(str.substring(str.lastIndexOf("/")+1).split('_completed')[0]);

Reference

.lastindexof()

.split()

answered Nov 11, 2013 at 16:45

Tushar Gupta - curioustushar

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1 Comment

user385729 Over a year ago

Thanks you solved my problem; I just added split('')[0] at the very end to get the first part and then split('')[1] for the second part to get rid of "_" in between Thanks

Álvaro González · Accepted Answer · 2013-11-11 16:45:37Z

1

In case a non-regexp solution is acceptable:

<?php
$url = 'http://localhost/project-1/uploaded_images/output//11-03-2013+11-09-2013/Brian_Brown_completed.jpg';
$test = basename($url, '_completed.jpg');

answered Nov 11, 2013 at 16:45

Álvaro González

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Comments

deceze · Accepted Answer · 2013-11-11 16:48:24Z

0

if (preg_match('~([^/]+)_completed\.jpg$~', $url, $match)) {
    echo $match[1];
}

answered Nov 11, 2013 at 16:48

deceze♦

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Barmar · Accepted Answer · 2013-11-11 16:49:00Z

0

PHP:

preg_match('#.*/(.*)_completed\.jpg$#', $input, $match); // Find the name
$name = str_replace('_', ' ', $match[1]); // Convert underscores to spaces

Javascript:

name = /.*\/(.*)_completed\.jpg$/.exec(input)[1].replace(/_/, ' ');

answered Nov 11, 2013 at 16:49

Barmar

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Comments

Malis · Accepted Answer · 2013-11-11 16:49:05Z

0

This should do:

$s = str_replace ("_", " ", substr ( $s, strrpos($s, "/")+1, strrpos($s, "_completed")-strrpos($s, "/")-1 )) ;

answered Nov 11, 2013 at 16:49

Malis

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