Selenium JAVA get parameter from a URL

Question

I have the following URL that I need to get the 4805206 code from.

 href="http://adserver.adtech.de/adlink|832|4805206|0|1686|AdId=9624985;BnId=1;itime=527032581;nodecode=yes;link=http://URL/Recruiters/Lex-Consultancy-3979.aspx"

I was wondering if its possible to do this and if so how?

Heres my Java Selenium Class

    public void checkAdTechKeys(WebDriver driver) {

    if(driver.getCurrentUrl().equalsIgnoreCase("URL"))
    {
        HP_LeftSearchBox(driver);//enter search terms
        driver.get("URL");
        // driver.findElement(By.linkText("Read     More")).getAttribute("href").toString();
                    String url = new String(driver.findElement(By.linkText("Read More")).getAttribute("href").toString());
                //  url = url.split("|")[2];
                 System.out.println(url);
    }else{
        setup.loadHomePage(driver);
        checkAdTechKeys(driver);
    } 
}

Illia · Accepted Answer · 2013-10-23 12:37:49Z

4

The code with a small modification that prints out that number:

driver.get("http://irishjobs.ie/");
String url = driver.findElement(By.linkText("Read More")).getAttribute("href");
String[] parsedUrl = url.split("\\|");
System.out.println(parsedUrl[2]);

Two things that you missed:

escaping the "|"
.split() returns an array of strings, not a string.

answered Oct 23, 2013 at 12:37

Illia

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