PHP Time function issue

Question

I need to add X days to current time

    echo date("d.m.Y H:i",time());
    echo "<br>";
    echo date("d.m.Y H:i",time()+5*24*60*60);

return correct results

    18.10.2013 14:22
    23.10.2013 14:22

but if i change 5 to 10 then

    18.10.2013 14:22
    28.10.2013 13:22

13:22 instead of 14:22 in result. 1 hour is missed.

What can be with it?

What happens if you'd use the following code? $date = strtotime(date("Y-m-d", strtotime($date)) . " +1 day"); — lt.kraken
– lt.kraken, Commented Oct 18, 2013 at 11:28
@str learn something new everyday - have been doing that for years "just incase" thanks — ɴᴀᴛᴇ ᴅᴇᴠ
– ɴᴀᴛᴇ ᴅᴇᴠ, Commented Oct 18, 2013 at 11:32

spacebean · Accepted Answer · 2013-10-18 11:28:15Z

1

Daylight savings ends on the 27th of October (so we fall back an hour) which explains the issue you are seeing. Try it with another month and you will get the expected result!

answered Oct 18, 2013 at 11:28

spacebean

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Comments

Adam · Accepted Answer · 2013-10-18 11:36:06Z

0

Use strtotime function:

examples:

echo date("d.m.Y H:i",strtotime("+10 days")) ;
echo date("d.m.Y H:i",strtotime("+6 hours 30 seconds"))

strtotime function ignores the transition to winter time.

EXAMPLE IN USE

edited Oct 18, 2013 at 11:36

answered Oct 18, 2013 at 11:27

Adam

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Comments

Jacko07 · Accepted Answer · 2013-10-18 12:03:16Z

0

To add day to a date you can use DateTime (maybe will be easier)

php.net DateTime

answered Oct 18, 2013 at 12:03

Jacko07

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