How to upload a file in Symfony 1.2 without using a specific form

Inside the action, after you bind the params to the form:

  $file = $your_form->getValue('your_file_field');

  $filename  = $file->getOriginalName(); //or whatever name
  $extension = $file->getExtension($file->getOriginalExtension());
  $file->save(sfConfig::get('sf_upload_dir').'/'.$filename.$extension);

btw, you can find the documentation for Symfony 1.2 in the corresponding Symfony Forms in Action book: Chapter 02 file upload

ps : Don't forget to manually add the enctype="multipart/form-data" to your html form!

Thank you friend. I'm looking for this code for 2 days. I'm new to php even i'm trying symfony. My code for symfony.

$this->filetype = $_FILES['file']['type'];
foreach ( $request -> getFiles () as  $file )
{ 
    if(move_uploaded_file ( $file [ "tmp_name" ],  sfConfig::get('sf_upload_dir').'/myfile/'.  $file [ 'name' ]))
    { 
        $this-setTemplate('success');
    } 
    else
    {
        $this-setTemplate('failure')
    }
} 

same way use the $filetype to check the uploaded file type. Check php file reference. For file types. Enjoy..

If you're still looking why you can't access to the uploaded file using $request->getFiles(), it might be because you forgot to add enctype="multipart/form-data".

Actually, you should have a form like this:

<form enctype="multipart/form-data" action="/yourdestination" method="post">
   <input type="file" name="somedummyfile"/>
   <input type="submit" value="Send"/>
</form>

And your action should do something like this:

$dummyfile = $request->getFiles('somedummyfile');
echo $dummyfile['tmp_name']; // Current filepath
echo $dummyfile['name']; // filename

Hope it helps !