Python Regular Expression: Replace Withing a group

Question

Is there a way to do substitution on a group?

Say I am trying to insert a link into text, based on custom formatting. So, given something like this:

This is a random text. This should be a [[link somewhere]]. And some more text at the end.

I want to end up with

This is a random text. This should be a <a href="/link_somewhere">link somewhere</a>. And some more text at the end.

I know that '\[\[(.*?)\]\]' will match stuff within square brackets as group 1, but then I want to do another substitution on group 1, so that I can replace space with _.

Is that doable in a single re.sub regex expression?

falsetru · Accepted Answer · 2013-10-06 06:18:23Z

3

You can use a function as a replacement instead of string.

>>> import re
>>> def as_link(match):
...     link = match.group(1)
...     return '<a href="{}">{}</a>'.format(link.replace(' ', '_'), link)
...
>>> text = 'This is a random text. This should be a [[link somewhere]]. And some more text at the end.'
>>> re.sub(r'\[\[(.*?)\]\]', as_link, text)
'This is a random text. This should be a <a href="link_somewhere">link somewhere</a>. And some more text at the end.'

answered Oct 6, 2013 at 6:18

falsetru

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hwnd · Accepted Answer · 2013-10-06 06:59:15Z

1

You could do something like this.

import re

pattern = re.compile(r'\[\[([^]]+)\]\]')

def convert(text): 
    def replace(match):
        link = match.group(1)
        return '<a href="{}">{}</a>'.format(link.replace(' ', '_'), link)
    return pattern.sub(replace, text)

s = 'This is a random text. This should be a [[link somewhere]]. .....'
convert(s)

See working demo

edited Oct 6, 2013 at 6:59

answered Oct 6, 2013 at 6:21

hwnd

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2 Comments

Goro Over a year ago

Yes, and I think this will not work if there are more than two words within the link.

hwnd Over a year ago

Updated with better answer.

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