Sort N-D numpy array by another 1-D array

Question

From the answer to this question (Sort a numpy array by another array, along a particular axis, using less memory), I learned how to sort a multidimensional numpy array a by the values of another numpy array b without creating too many additional arrays.

However, numpy.rec.fromarrays([a, b]) only works if the arrays a and b have the same shape. My b array is 1-D array, but a array is a N-D array (N is not specified). Is it a nice way (and efficient) to sort the a array among a particular axis by the value of the 1-D array b?

Jaime · Accepted Answer · 2013-09-27 19:41:20Z

Use np.take with the axis keyword argument:

>>> a = np.arange(2*3*4).reshape(2, 3, 4)
>>> a
array([[[ 0,  1,  2,  3],
        [ 4,  5,  6,  7],
        [ 8,  9, 10, 11]],

       [[12, 13, 14, 15],
        [16, 17, 18, 19],
        [20, 21, 22, 23]]])
>>> b = np.arange(3)
>>> np.random.shuffle(b)
>>> b
array([1, 0, 2])
>>> np.take(a, b, axis=1)
array([[[ 4,  5,  6,  7],
        [ 0,  1,  2,  3],
        [ 8,  9, 10, 11]],

       [[16, 17, 18, 19],
        [12, 13, 14, 15],
        [20, 21, 22, 23]]])

If you want to use fancy indexing, you just need to pad the indexing tuple with enough empty slices:

>>> a[:, b]
array([[[ 4,  5,  6,  7],
        [ 0,  1,  2,  3],
        [ 8,  9, 10, 11]],

       [[16, 17, 18, 19],
        [12, 13, 14, 15],
        [20, 21, 22, 23]]])

Or in a more general setting:

>>> axis = 1
>>> idx = (slice(None),) * axis + (b,)
>>> a[idx]
array([[[ 4,  5,  6,  7],
        [ 0,  1,  2,  3],
        [ 8,  9, 10, 11]],

       [[16, 17, 18, 19],
        [12, 13, 14, 15],
        [20, 21, 22, 23]]])

But np.take should really be your first option.

Collectives™ on Stack Overflow

Sort N-D numpy array by another 1-D array

1 Answer 1

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related