object object in php from ajax?

Question

In my php I'm getting

string(15) "[object Object]"

I'm posting from ajax an array consisting of:

ctx.imageData.push({name : file.name, value : this.result});

this.result is a base64 encoded image, taken from a js file reader.

How can I get the contents of object object in php?

"I'm posting from ajax" — How? You need to show enough code for people to be able to reproduce the problem. — Quentin
– Quentin, Commented Sep 17, 2013 at 10:43
@Quentin it doesnt matter how Im posting from ajax, the data is being sent. This is a problem with php — panthro
– panthro, Commented Sep 17, 2013 at 11:02
@panthro — [Object object] is how JavaScript (by default) stringifies an object. Since JavaScript is generating that string, the problem must be on the JavaScript side. — Quentin
– Quentin, Commented Sep 17, 2013 at 11:05

Kelu Thatsall · Accepted Answer · 2013-09-17 10:49:27Z

2

You probably try to push an object with javascript which is being cast to string. In PHP we get the result string(15) "[object Object]" because the string is actually [object Object] and you cannot get any information from it within PHP. You are making some mistake while passing the variable with javascript and you have to show us some more code to help you handle it.

answered Sep 17, 2013 at 10:49

Kelu Thatsall

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Ashwini Agarwal · Accepted Answer · 2013-09-17 10:51:42Z

1

ctx.imageData.push({name : file.name, value : JSON.stringify(this.result)});

And use json_decode in php.

jQuery does not have functionality of its own for that, you have to use the browser built-in version or json2.js from http://www.json.org

JSON.stringify() is available in all major browsers, but to be compatible with older browsers you still need that fallback.

edited Sep 17, 2013 at 10:51

answered Sep 17, 2013 at 10:43

Ashwini Agarwal

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4 Comments

panthro Over a year ago

json_decode just comes back with NULL, even with adding json_decode($myVar, true)

Ashwini Agarwal Over a year ago

Try console.log(JSON.stringify(this.result)); and see what you get??

panthro Over a year ago

"data:image/jpeg;base64,/9j/4QAYRXhpZgAASUkqAAgAAAAAAAAAAAAAAP/sABFEdWNreQAB…1qMXeO+34oaxuI22+Ki/o8P/6Ht/SP/wCp9v4/P/b9nX/4vN/4dV6/Hf4ft/gs3p8N/j+zr//Z"

panthro Over a year ago

string(15) "[object Object]"

Jorge Y. C. Rodriguez · Accepted Answer · 2013-09-17 11:42:29Z

0

try json_decode() on the variable that you are getting in the php, and after that use var_dump to check its value

edited Sep 17, 2013 at 11:42

Jorge Y. C. Rodriguez

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answered Sep 17, 2013 at 10:42

nshah

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1 Comment

Jorge Y. C. Rodriguez Over a year ago

Try to elaborate better this answer ;)

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