How can I create a Dynamic array that holds Integer values (not int) in PROCESSING.
I have stored the String into a text file (String Str= "12,13,14,15"). Now i need to split and convert them to Integer type after loading the text file.
3 Answers
Since code is reading a file, I would use a Scanner instead:
String str = "2,3,4,5,6,7";
List<Integer> intList = new ArrayList<Integer>();
Scanner sc = new Scanner(new File(/*yourFile*/));
//Scanner sc = new Scanner(str);
while(sc.hasNext()) {
sc.useDelimiter(",");
intList.add(sc.nextInt());
}
Integer[] wrapperArray = new Integer[intList.size()];
intList.toArray(wrapperArray);
Scanner: How-to
1 Comment
MELWIN
there is no keyword Scanner in processing 2 :(
You can try this code.. It works fine for me
try {
FileReader fr = new FileReader("data.txt");
BufferedReader br = new BufferedReader(fr);
String str = br.readLine();
String strArray[] = str.split(",");
Integer intArray[] = new Integer[strArray.length];
for (int i = 0; i < strArray.length; i++) {
intArray[i] = Integer.parseInt(strArray[i]);
System.out.println(intArray[i]);
}
} catch (Exception e) {
// TODO: handle exception
e.printStackTrace();
}
I hope this will help you.
Comments
String str = "12,13,14,15";
String[] strArray = str.split(",");
int[] intArray = new int[strArray.length];
for (int i = 0; i < strArray.length; i++) {
try {
intArray[i] = Integer.parseInt(strArray[i]);
} catch (NumberFormatException e) {
// Handle the exception properly as noted by Jon
e.printStackTrace();
}
}
9 Comments
Jon Skeet
Note that just printing the stack trace is almost always the wrong way of handling exceptions. It's what IDEs tend to suggest automatically, but the code should pretty much never be left that way.
Saj
@JonSkeet Agreed but this should be handled by the designer how to handle it. I left it there so OP can handle it depending on the spec/design.
Jon Skeet
But without mentioning it (or indeed writing any explanatory text) you're basically inviting the OP to copy and paste your code without change. IMO you should have at least added a TODO comment... and ideally written some text in your answer as well as the code. (Code-only answers are almost always less useful than those with an explanation.)
Saj
@JonSkeet Done but didn't know that what you find in the net is good for direct "copy paste" in your project.
Jon Skeet
No, it's not a good idea - but that doesn't mean it doesn't happen :(
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new Integer[n]orArrayList<Integer>?