PHP date() function returning incorrect values

Question

I have a timestamp of "1377592503467" stored in a variable and when I pass it to php's date() function, it returns a value of "1935-05-26 03:04:11". Hopefully I am missing something obvious; below is my code. The timestamp represents 2013-08-27 15:57:45 but that's not what is being returned.

$date = "1377592503467";
$formattedDate = date("Y-m-d h:i:s", $date);

Thank you.

deceze · Accepted Answer · 2013-08-27 16:23:00Z

7

Looks like that timestamp is in milliseconds, not seconds as PHP uses them.

Do date(..., $date / 1000).

answered Aug 27, 2013 at 16:23

deceze♦

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5 Comments

Alma Do Over a year ago

I'm not sure it's exactly in milliseconds, since (GMT+04): 2013-08-27 08:35:03 is a corresponding date for 1377592503

deceze Over a year ago

@Alma True, but at least it gets you into the right ballpark. I'm not aware of a generally applicable timestamp format which in addition has a few hours of skew, so I'd just err on the side of the OP providing incorrect information. :)

Alma Do Over a year ago

I wanted to ask in comment why OP providing timestamp larger than 2^31-1 (i.e. max for signed longint) - but since there's high rated answer, it seems, you're correct.

Amal Over a year ago

I don't know how the OP got that timestamp, but the microsecond explanation makes more sense. See this.

Brian Costea Over a year ago

Thanks deceze! Appreciate the help from all. I used the /1000 as a solution.

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