Passing char pointer array as parameter

Question

How can I pass a char* array as a parameter, without creating one and initializing it?

This code works (creating an initializing one):

char *messages[] = {"Zero", "One", "Two", "Three"};
printf("%s", messages[1]);

But it wont work if you pass it like so:

#include <stdio.h>

void printElement1(char *messages[]) {
    printf("%s", messages[1]);
}

int main(void) {

    printElement1({"Zero", "One", "Two", "Three"});

    return 1;
}

I cannot use a va_list, the function takes a char* array and that's that.

Carl Norum · Accepted Answer · 2013-08-26 20:53:19Z

6

You're just missing the type for your compound literal. Change that line to:

printElement1((char *[]){"Zero", "One", "Two", "Three"});

and it will work fine.

answered Aug 26, 2013 at 20:53

Carl Norum

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2 Comments

Jimmay Over a year ago

Wow! That's incredible, I had no idea you could type cast like this.

Carl Norum Over a year ago

It's not a typecast, it's a compound literal.

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