Send multiple arrays and a string using json from ajax to php and receiving them on php

Question

These are the two arrays which are sent from ajax call to php

var mycol=new Array(); 
var mycolval=new Array();
var inputs = document.getElementsByTagName("input");
            for (var i = 1; i < inputs.length; i++)
            {
                if($("#"+inputs[i].id).val().length>0)
                    {   
                        flag=true;
                        mycol=inputs[i].id;
                        mycolval=$("#"+inputs[i].id).val();


                    }

            }

And this is the string

var string = $('#search_input').val();

I have tried the following code but it doesn't seem to work. Please help me come up with solution.

$.ajax({
    url: "anding.php",
    type: "POST",
    dataType: 'json',
    data: JSON.stringify(mycol:mycol,mycolval:mycolval,string:string),
    success: function(response){}

   });

Why does it not work? What behaviour are you expecting that you don't see? Do you get any errors in the console? — Rory McCrossan
– Rory McCrossan, Commented Aug 10, 2013 at 19:05

Musa · Accepted Answer · 2013-08-10 19:27:10Z

1

Your code syntax is wrong

    data: JSON.stringify(mycol:mycol,mycolval:mycolval,string:string),

should be

    data: JSON.stringify({mycol:mycol,mycolval:mycolval,string:string}),

You might want also want to specify the content type since you're sending JSON

contentType: 'application/json',

then you can access you data

$postdata = json_decode(file_get_contents("php://input"), true);
$mycol = $postdata['mycol'];

though I am skeptical you actually want to send json but rather url encoded key value pairs so you can access them via $_POST['mycol'] etc, if so use

        data: {mycol:mycol,mycolval:mycolval,string:string},

instead.

Also

$("#"+inputs[i].id).val()

could be simplified into

inputs[i].value

edited Aug 10, 2013 at 19:27

answered Aug 10, 2013 at 19:14

Musa

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5 Comments

roshan Over a year ago

How do i access stringify data in php?

roshan Over a year ago

mycol and mycolval are not key value pair.

Musa Over a year ago

@roshan what is that suppose to mean?

roshan Over a year ago

What am i supposed to write instead of ("php://input").

Musa Over a year ago

@roshan that is what you suppose to write.

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