What is the shortest way to create this array in Ruby:
[10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
Thanks for any help!
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2It depends on your intention. Do you want to start with 10 and skip by 10 until 100, or do you want to divide between 10 and 100 evenly with 10, etc?sawa– sawa2013-08-05 13:30:07 +00:00Commented Aug 5, 2013 at 13:30
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1What have you written? What did searches for this reveal?the Tin Man– the Tin Man2013-08-05 14:24:07 +00:00Commented Aug 5, 2013 at 14:24
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3 Answers
What about Range#step:
(10..100).step(10).to_a
#=> [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
Or Numeric#step:
10.step(100, 10).to_a
#=> [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
2 Comments
Arup Rakshit
You second one is nice one to know... for me... :) Now I stopped thinking about any alternative solutions..
the Tin Man
#2 is what I was going to recommend.
You can use Range and call Enumerable#map method on it, like this:
(1..10).map{|i| i * 10}
# => [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
Or, as suggested by @JörgWMittag, with Object#method method that returns Method instance which is converted to proc by & notation:
(1..10).map(&10.method(:*))
# => [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
Comments
This builds an array directly from the constructor.
Array.new(10){|i| (i + 1) * 10}
# => [10, 20, 30, 40, 50, 60, 70, 80, 90, 100]
