I have a referrer URL like this:
http://myUrl.com?page=thisPage&gotoUrl=https://yahoo.com?gotoPage
How do I get the Values of "page" and "gotoUrl" in my Spring Controller?
I want to store these values as variables, so I can reuse them later.
3 Answers
In SpringMVC you can specify values from the query string be parsed and passed in as method parameters with the @RequestParam annotation.
public ModelAndView getPage(
@RequestParam(value="page", required=false) String page,
@RequestParam(value="gotoUrl", required = false) String gotoUrl) {
}
Comments
You can use the getParameter() method from the HttpServletRequest interface.
For example;
public void getMeThoseParams(HttpServletRequest request){
String page = request.getParameter("page");
String goToURL = request.getParameter("gotoUrl");
}
5 Comments
Jake
This makes sense, if I want to pass the request as an argument. But is there a way to retrieve parameters, if I don't want to pass HttpServletRequest as an Argument to my controller action?
Akshay
While this answer is technically correct, its not the recommended way to do it with Spring, @Affe's answer is more to the point.
Lukasz Wiktor
@AkshaySinghal unless you don't know the parameters in advance but you need a way to handle them - then you can use
request.getParameterNames() or request.getParameterMap()Akshay
@LukaszWiktor I'm sorry I don't understand that comment. It does not seem related to any question or answer.
Lukasz Wiktor
@AkshaySinghal I wanted to say that Raunak's answer was helpful. In my case I don't know exact names of the parameters. I need to create an endpoint that can read any parameter. When I noticed this answer I discovered also the 2 methods mentioned in my previous comment.
Get the QueryString in Spring MVC Controller
This is Liferay portal specific solution, and it works.
Query String Example: ?reportTypeId=1&reportSeqNo=391
In order to get the value of reportSeqNo in Liferay Portal, we need to get the Original Servlet Request.
String reportSeq = PortalUtil.getOriginalServletRequest(PortalUtil.getHttpServletRequest(renderRequest)).getParameter("reportSeqNo");
Comments
gotoUrl(although I'm not sure it would functionally matter in this particular example).