C# 3 dimensional array

Question

I want to store ARRAY from 3 dimensional array into buildingCostIds, but it says I MUST have 3rd number.

public static int[, ,] buildingCost = { {{0,1,2},{5,5,5}}};

public static void addBuilding(int[] ids, int[] amounts, int buildingId)
{
    int[] buildingCostIds = buildingCost[buildingId, 0, *];
}

*I need third number here, but I don't want it because it will extract just number, I want whole array!

PROBLEM SOLVED, solution:

public static Array extractArray(int dim1, int dim2)
{
    int[] tempArray = { };

    for (int number=0;number<=2; number++)
    {
    tempArray[number] = buildingCost[dim1, dim2, number];
    }
    return tempArray;
}

If you have found a solution, please mark the appropriate answer as accepted (even if that means adding an answer with your solution yourself and marking it as accepted possibly after waiting for a while. — O. R. Mapper
– O. R. Mapper, Commented Jul 27, 2013 at 9:43

Community · Accepted Answer · 2017-05-23 10:26:56Z

5

This might be simpler if you use an array-of-arrays, or jagged array [][][] like

int[][][] buildingCost = new int[2][][];

Then you can access buildingCost[buildingId, 0] which is an array of ints.

There is a related question here

EDIT

Be aware the "problem solved" you added to the question duplicates the data, so you may run out of memory if you keep doing this. Consider using a List of Lists of Lists and lazy evaluating what you need.

edited May 23, 2017 at 10:26

CommunityBot

11 silver badge

answered Jul 27, 2013 at 9:22

doctorlove

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1 Comment

matijakevic Over a year ago

No, I have much data and I'm lazy to write all them down like that. Found a solution! I'll post it!

WinHtaikAung · Accepted Answer · 2019-05-15 06:27:20Z

2

Try This

int[, ,] array3D = new int[3,3,3]

edited May 15, 2019 at 6:27

answered Jul 27, 2013 at 9:23

WinHtaikAung

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2 Comments

doctorlove Over a year ago

How does this help to access the last column?

Max Voisard Over a year ago

lol Stack Overflow rendered it as the try and this keywords

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