walking through php array

Question

Can anyone point me in the right direction with the below

I have this HTML in a FROM (simplified for this example):

=============== Start HTML ===================

<select name="Postage[]" id="Unique-ID">
    <option value="1">Postage Option 1</option>
    <option value="2">Postage Option 2</option>
    <option value="3">Postage Option 3</option>
</select>
<input name="PostagePrice[]" id="Price-Unique-ID" value="" />

<select name="Postage[]" id="Unique-ID">
    <option value="1">Postage Option 1</option>
    <option value="2">Postage Option 2</option>
    <option value="3">Postage Option 3</option>
</select>
<input name="PostagePrice[]" id="Price-Unique-ID" value="" />

<select name="Postage[]" id="Unique-ID">
    <option value="1">Postage Option 1</option>
    <option value="2">Postage Option 2</option>
    <option value="3">Postage Option 3</option>
</select>
<input name="PostagePrice[]" id="Price-Unique-ID" value="" />

================== End HTML =====================

I am collecting this from the form and setting it to an array ($arrPostageOptions) with the below code:

=============== Start PHP ===================

if (isset($_POST['Postage'])) {
    if (is_array($_POST['Postage'])) {
        $n = count($_POST['Postage']);
        for ($i = 0; $i < $n; ++$i) {
            // check to only collect completed entries
            if( !empty($_POST['Postage'][$i]) && !empty($_POST['PostagePrice'][$i]) ){
                // assign to array
                $arrPostageOptions[$i] = array( "Postage" => $_POST['Postage'][$i], "PostagePrice" => $_POST['PostagePrice'][$i], );
            }
        }
    }
}

=============== End PHP ===================

This results in the following array

============ array result ===============

Array(
    [0] => Array
        (
            [Postage] => 1
            [PostagePrice] => 12
        )
    [1] => Array
        (
            [Postage] => 2
            [PostagePrice] => 24
        )
    [2] => Array
        (
            [Postage] => 3
            [PostagePrice] => 48
        )
)

============ end array result ===============

The answer (I think) I want is for each array is :

(that the array numbers match the postage numbers is just coincidence, I only want ‘Postage’ and ‘PostagePrice’)

I am trying the following:

=========== start of what I am trying ==========

foreach ($arrPostageOptions as $id) {
    while ($id) {
        $Postage = $id["Postage"];
        $PostagePrice = $id["PostagePrice"];
        // echo $Postage.' '.$PostagePrice.'<br>';
        unset($id);
        if (!$listing_obj->addPostageOptions($ListingID, $PostageOptionID, $PostagePrice, $db)) {
           $err_text .= 'An error occurred adding Postage Option'.$PostageOptionID;
        }
    }   
}

====== end of what I am trying ==============

Unfortunately this is not working as I expect (but is the closest I have gotten) . I have also tried multiple foreach loops, but again I don’t get what im after (unsettling the $id is stopping the loop from continuing for ever, but is also giving me PHP notices of Undefined variable $id)

I’m sure I know how to do this, but seem to have forgotten and have possible over complicated it as these arrays are still confusing the s**t out of me.

Any advice would be greatly welcomed!

I don't think it should be name="Postage[]"... maybe name="Postage". — Brian
– Brian, Commented Jul 20, 2013 at 18:29

Thomas Leu · Accepted Answer · 2013-07-20 18:34:09Z

1

Why not simply:

foreach ($arrPostageOptions as $postageOption) {
    $postage = $postageOption["Postage"];
    $postagePrice = $postageOption["PostagePrice"];
    echo $postage.' '.$postagePrice.'<br>';
    ...
}

Sorry for renaming, but $id was too confusing for me.

answered Jul 20, 2013 at 18:34

Thomas Leu

8554 silver badges13 bronze badges

Sign up to request clarification or add additional context in comments.

4 Comments

Thomas Leu Over a year ago

if that doesn't work for you try once var_dump($postageOption) inside the loop...

Ford Over a year ago

works perfect this time...... thank you, i think i was having a mind block moment, as im sure this was what i first tried and the reslt was "P"... hmmm.... thank you!

Thomas Leu Over a year ago

you're welcome :-) Btw it's not a good idea to have more than 1 element in a document with the same id.

Ford Over a year ago

yes, i will remove the elements with the same id, i just added it like that for the example

Joe Minichino · Accepted Answer · 2013-07-20 18:26:56Z

1

I'm not entirely sure I understood what you want to do but it would seem to me that you want to iterate the array like this, but I'm not sure.

foreach ($arrPostageOptions as $id=>$array) {
  foreach($array as $key=>$val){
    // do your stuff here using where you can also reference $id
  }
}

answered Jul 20, 2013 at 18:26

Joe Minichino

2,76524 silver badges20 bronze badges

Comments

Shawn Frank · Accepted Answer · 2013-07-20 18:58:14Z

there are a couple of things I would like to say is that the isset function is a bit pointless here and it is best used along with a submit button, not for text fields and other inputs.

Also, you are declaring your array inside the loop so accessing it anywhere outside will give an undefined error.

I just used your form and updated the php script slightly to give the output you desire. Please have a look.

Your form

<form action="yourscript.php" method="POST">

    <select name="Postage[]" id="Unique-ID">
    <option value="1">Postage Option 1</option>
    <option value="2">Postage Option 2</option>
    <option value="3">Postage Option 3</option>
    </select>
    <input name="PostagePrice[]" id="Price-Unique-ID" value="" />

    <select name="Postage[]" id="Unique-ID">
        <option value="1">Postage Option 1</option>
        <option value="2">Postage Option 2</option>
        <option value="3">Postage Option 3</option>
    </select>
    <input name="PostagePrice[]" id="Price-Unique-ID" value="" />

    <select name="Postage[]" id="Unique-ID">
        <option value="1">Postage Option 1</option>
        <option value="2">Postage Option 2</option>
        <option value="3">Postage Option 3</option>
    </select>
    <input name="PostagePrice[]" id="Price-Unique-ID" value="" />

    <input type="submit" value="submit" name="submit"/>

    </form>

I added a submit button and a the method and action in the header just to make it a bit more clear.

And here is the script I used, pretty similar to yours

<?php

    $arrPostageOptions = array();

    if(isset($_POST['submit']))
    {
        $postage = $_POST['Postage'];
        $postagePrice = $_POST['PostagePrice'];

        $array_size = count($postage);

        for($i = 0; $i < $array_size; $i++)
        {
            if(!empty($postage[$i]) && !empty($postagePrice[$i]))
            {
                $arrPostageOptions[$i] = array("Postage"=>$postage[$i], 
                            "PostagePrice"=>$postagePrice[$i]);  
            }
        }
        print_r($arrPostageOptions);
    }

?>

I check if the submit button is set/clicked and enter the loop. I define the array variable outside so it can be used anywhere in the program.

If you see the print_r result, you will see the array in the format you desire.

I hope I answered a couple of your questions.

At the same time, its better to always put your POST data into variables before using them so you can check them and control them better than directly using $_POST['name']. This will be of more use when you work with databases and other related things.

Hope this helps.

Thanks, Shawn.

JAL · Accepted Answer · 2013-07-20 18:28:57Z

0

The while within the foreach is redundant. foreach will only continue as long as there is a new entry to become $id anyhow.

The loop should be fine if you remove the while. If you want to test whether the data is valid, test on the array keys themselves like by putting this in the loop

if(!$id["Postage"] || !$id["PostagePrice"]){
  continue;  
  }

answered Jul 20, 2013 at 18:28

JAL

21.6k1 gold badge50 silver badges67 bronze badges

Collectives™ on Stack Overflow

walking through php array

4 Answers 4

4 Comments

Comments

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

4 Answers 4

4 Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related