I have a ruby file that I would normally run in command line as follows:
ruby file.rb YYYY-MM-DD YYYY_MM_DD
I want to write a bash script to run this file where both YYYY-MM-DD are strings for yesterday's date.
How would I do that?
-
What does this have to do with STDIN? Command line arguments are not STDIN.hyde– hyde2014-03-02 14:54:47 +00:00Commented Mar 2, 2014 at 14:54
Add a comment
|
2 Answers
ruby file.rb $(date -d yesterday +'%Y-%m-%d') $(date -d yesterday +'%Y_%m_%d')
Note that this will only work in bash. Other Bourne-like shells will work if you use backticks instead of $().
1 Comment
tripleee
The caveat is wrong;
$(command) should work in any POSIX shell. If you're on something truly ancient like SunOS 3, then maybe.See "YYYY-MM-DD format date in shell script" to figure out how to get the date in whatever format you want.
Yesterday's date can be found as:
date -d '1 day ago' +'%Y/%m/%d'
from "How To Get Yesterday’s Date using BASH Shell Scripting".
Replace the / with - or _ and then pass them in to the Ruby statement.
Edit: Vote for the other guy. Their answer actually has code.
